NEET-XII-Chemistry

Previous Year Paper year:2017

with Solutions - page 2

Note: Please signup/signin free to get personalized experience.

Note: Please signup/signin free to get personalized experience.

10 minutes can boost your percentage by 10%

Note: Please signup/signin free to get personalized experience.

 
  • Qstn #16
    Match the interhalogen compounds of column I
    with the geometry in column II and assign the
    correct code.
    Column I Column II
    (a ) XX′ (i) T - shape
    (b) XX′3 (ii) Pentagonal bipyramidal
    (c) XX′5 (iii) Linear
    (d) XX′7 (iv) Square - pyramidal
    (v) Tetrahedral
    Code :
    (a ) (b) (c) (d)
    (1) (iv) (iii) (ii) (i)
    (2) (iii) (iv) (i) (ii)
    (3) (iii) (i) (iv) (ii)
    (4) (v) (iv) (iii) (ii)
    digAnsr:   3
    Ans : (3)
    Sol. (a) XX1 sp3 Linear
    (b) 13XX sp
    3d T-shape
    (c) 15XX sp
    3d2 square pyramid
    (d) 17XX sp
    3d3 Penta genal planar
    a ⇒ iii
    b ⇒ (i)
    c ⇒ (iv)
    d ⇒ (ii)
  • Qstn #17
    Mixture of chloroxylenol and terpineol acts as :
    (1) antibiotic
    (2) analgesic
    (3) antiseptic
    (4) antipyretic
    digAnsr:   3
    Ans : (3)
    Sol. Mixture of Chloroxylenol and terpineol is called dettol which acts as an antiseptic.
  • Qstn #18
    It is because of inability of ``ns^2`` electrons
    of the valence shell to participate in bonding that :
    (1) ``Sn^{4+}`` is reducing while ``Pb^{4+}`` is oxidising.
    (2)``Sn^{2+}`` is reducing while ``Pb^{4+}`` is oxidising.
    (3) ``Sn^{2+}`` is oxidising while ``Pb^{4+}`` is reducing.
    (4) ``Sn^{2+}`` and ``Pb^{2+}`` are both oxidising and reducing.
    digAnsr:   2
    Ans : (2)
    Sol. Due to inert pair effect Pb+2 is more stable where as in tin Sn+4 is more stable.
    ∴ Pb+4 will get reduce and Sn+2 will get Oxidize.
    [Pb+4 = oxidising agent, Sn+2 = reducing agent]





  • Qstn #19
    Extraction of gold and silver involves
    leaching with ``CN^-`` ion. Silver is later recovered by :
    (1) displacement with Zn
    (2) liquation
    (3) distillation
    (4) zone refining
    digAnsr:   1
    Ans : (1)
    Sol. Silver is extracted by cyanide process involving :
    1. Complex formation
    2. Metal displacement with zinc
    Ag2S ⎯⎯ →⎯NaCN Na [Ag(CN)2] + Na2S
    Zn
    Ag + Na2 [Zn(CN)4]
  • Qstn #20
    A 20 litre container at 400 K contains ``CO_2``(g)
    at pressure 0.4 atm and an excess of SrO (neglect the
    volume of solid SrO). The volume of the container is now
    decreased by moving the movable piston fitted in the
    container. The maximum volume of the container, when
    pressure of ``CO_2`` attains its maximum value, will be :
    (Given that : ``SrCO_3``(s) ``\xrightleftharpoons{K}`` SrO (s) + ``CO_2`` ( g),
    ``K_p`` = 1.6 atm)
    (1) 2 litre
    (2) 5 litre
    (3) 10 litre
    (4) 4 litre
    digAnsr:   2
    Ans : (2)
    Sol.
    )s(
    3SrCO )s(
    SrO +
    )g(
    2CO
    At maximum pressure of CO2
    Kp = 2COP = 1.6 atm
    Temperature is constant
    ∴ P1V1 = P2V2
    0.4 × 20 = 1.6 × V2
    V2 = 5 lit
  • Qstn #21
    Which is the incorrect statement ?
    (1) Frenkel defect is favoured in those ionic compounds
    in which sizes of cation and anions are almost equal
    (2) FeO0.98 has non stoichiometric metal deficiency defect
    (3) Density decreases in case of crystals with Schottky's defect
    (4) NaCl(s) is insulator, silicon is semiconductor, silver
    is conductor, quartz is piezo electric crystal
    digAnsr:   1
    Ans : (1)
    Sol. Frenkel defect is favoured in those ionic compounds in which sizes of cation and anions are not equal . i.e.
    cation is small in size





  • Qstn #22
    Which of the following is dependent on temperature ?
    (1) Weight percentage
    (2) Molality
    (3) Molarity
    (4) Mole fraction
    digAnsr:   3
    Ans : (3)
    Sol. Molarity depends upon temperature
    VM
    1000W
    M
    A
    A
    ×
    ×
    =
    V ∝ T
    T ↑ , V ↑,, Molarity (↓)
  • Qstn #23
    The correct order of the stoichiometries of AgCl
    formed when AgNO3 in excess is treated with the complexes :
    ``CoCl_3.6NH_3, CoCl_3.5NH_3, CoCl_3.4NH_3`` respectively is -
    (1) 2AgCl, 3AgCl, 1AgCl
    (2) 1AgCl, 3AgCl, 2AgCl
    (3) 3AgCl, 1AgCl, 2AgCl
    (4) 3AgCl, 2AgCl, 1AgCl
    digAnsr:   4
    Ans : (4)
    Sol. CoCl3.6NH3
    [Co(NH3)6]Cl3 ⎯⎯ →⎯ 3AgNO 3AgCl
    CoCl3.5NH3
    [Co(NH3)5Cl]Cl2 ⎯⎯ →⎯ 3AgNO 2AgCl
    CoCl3.4NH3
    [Co(NH3)4Cl2]Cl ⎯⎯ →⎯ 3AgNO 1AgCl
  • Qstn #24
    An example of a sigma bonded organometallic compound is -
    (1) Cobaltocene
    (2) Ruthenocene
    (3) Grignard's reagent
    (4) Ferrocene
    digAnsr:   3
    Ans : (3)
    Sol.
    Grignard's reagent (R mg x) is σ-bonded organometallic compound CH3-Mg-I
    Ferrocene, cobaltocene and Ruthenocene are π-bonded organometallic compound and they contain
    cyclopentadionyl ring





  • Qstn #25
    Which one is the wrong statement ?
    (1) The energy of 2s orbital is less than the energy
    of 2p orbital in case of Hydrogen like atoms
    (2) de-Broglie's wavelength is given by λ = ``\frac {h}{mv}``
    where m = mass of the particle, v = group velocity of the
    particle.
    (3) The uncertainty principle is ΔE X Δt ``\geq `` ``\frac{h} {4\pi}``
    (4) Half filled and fully filled orbitals have greater
    stability due to greater exchange energy, greater
    symmetry and more balanced arrangement
    digAnsr:   1
    Ans : (1)
    Sol. In hydrogen like atom energy 2s in equal to 2p (as in single electron species)
  • Qstn #26
    Which one is the most acidic compound ?
    (1)
    (2)
    (3)
    (4)
    digAnsr:   1
    Ans : (1)
    Sol. ∵ Acidic strength ∝ stability of anion
    |
    OH
    |
    NO2
    O2N NO2
    |
    O-
    |
    NO2
    O2N NO2 -H⊕
    Max. stable anion due to delocalised Θve charge & -M effect of all three NO2 group
  • Qstn #27
    A first order reaction has a specific reaction rate
    of ``10^{-2} sec^{-1}. How much time will it take for
    20 g of the reactant to reduce to 5g ?
    (1) 693.0 sec
    (2) 238.6 sec
    (3) 138.6 sec
    (4) 346.5 sec
    digAnsr:   3
    Ans : (3)
    Sol. For first order reaction

    CAREER POINT
    CAREER POINT, CP Tower, IPIA, Road No.1, Kota (Raj.), : 0744-6630500 | www.ecareerpoint.com Email: info@cpil.in Page # 11
    [ CODE - Y ]
    t
    0
    ]A[
    ]A[log
    t
    303.2k =
    5
    20log
    t
    303.210 2 =-
    4log
    10
    303.2t 2-=
    = 64.138
    10
    6020.0303.2
    2 =
    ×
    - sec
  • Qstn #28
    Consider the reactions :

    Identify A, X, Y and Z
    (1) A-Ethanol, X-Acetaldehyde, Y-Butanone Z-Hydrazone
    (2) A-Methoxymethane, X-Ethanoic acid, Y-Acetate ion, Z-Hydrazine
    (3) A-Methoxymethane, X-Ethanol, Y-Ethanoic acid, Z-Semicarbazide
    (4) A-Ethanal, X-Ethanol, Y-But-2-enal., Z-Semicarbazone
    digAnsr:   4
    Ans : (4)
    Sol.
    Cu
    573 K X
    Tollen's
    A Y
    Z
    O
    ||
    NH2-NH-C-NH2
    (Oxidation)
    Reagent Silver Mirror
    OH/Δ
    Θ
    aldol condensation
    semicarbazide
    X is CH3CH2-OH (Ethanol)
    A is CH3-CH=O (Ethanal)
    Y is CH3-CH=CH-CH=O (But-2-enal)
    Z is CH3-CH=N-NH-C-NH2
    ||
    O
    (Acetaldehyde-semicarbazone)


  • Qstn #29
    Machanism of a hypothetical reaction ``\ce X2+ Y2`` → 2XY is given below.
    ( i) ``X_ 2`` → X + X (fast)
    (ii) X + ``Y_2`` ``\rightleftharpoons`` XY + Y (slow)
    (iii) X + Y → XY (fast)
    The overall order of the reaction will be -
    (1) 1.5
    (2) 1
    (3) 2
    (4) 0
    digAnsr:   1
    Ans : (1)
    Sol. From slow step
    r = k [X] [Y2]
    but [X] is dummy reactant so it will replaced by step I
    ]X[
    ]X[K
    2
    2
    c =
    ]X[K]X[ 2c=
    ∴ 122
    1
    2
    2
    1
    c ]Y[]X[)K(Kr =
    so overall order = 5.11
    2
    1
    =+
  • Qstn #30
    Predict the correct intermediate and product in the
    following reaction :

    (1)
    (2)
    (3)
    (4)
    digAnsr:   1
    Ans : (1)
    Sol.
    CH3-C≡CH CH3-C=CH2
    OH
    H2O
    HgSO4
    (Markowinikoff
    addition)
    |
    T
    CH3-C-CH3
    O
    ||
    A B