NEET-XII-Chemistry

Previous Year Paper year:2017

with Solutions - page 3

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  • Qstn #31
    The IUPAC name of the
    compound is -
    (1) 3-keto-2-methylhex-5-enal
    (2) 3-keto-2-methylhex-4-enal
    (3) 5-formylhex-2-en-3-one
    (4) 5-methyl-4-oxohex-2en-5-al
    digAnsr:   2
    Ans : (2)
    Sol.
    O
    || CHO
    2 3
    4
    5 6
    1
    In IUPAC called 3-Keto-2-methyl hex-4-enal
  • Qstn #32
    In the electrochemical cell -
    Zn|``ZnSO_4``(0.01M) || ``CuSO_4`` (1.0 M)| Cu,
    the emf of this Daniel cell is ``E_1``. When the
    concentration of ``ZnSO_4`` is changed to 1.0 M
    and that of ``CuSO_4`` changed to 0.01M, the emf
    changes to E2. From the followings, which
    one is the relationship between E1 and E2 ?
    Given, ``\frac {RT}{F}`` = 0.059) .
    (1) E2 = 0 ≠ E1
    (2) E1 = E2
    (3) E1 < E2
    (4) E1 > E2
    digAnsr:   4
    Ans : (4)
    Sol.
    Cu||CuSO||ZnSO|Zn
    )M0.1(
    4
    )M01.0(
    4
    Nernst equation
    ]Cu[
    ]Zn[log
    2
    059.0EEmf 2
    2
    cell +
    +
    ° -=
    In first case
    1
    01.0log
    2
    059.0EE cell1 -=
    °
    In second case
    01.0
    1log
    2
    059.0EE cell2 -=
    °
    So E1 > E2






  • Qstn #33
    A gas is allowed to expand in a well insulated
    container against a constant external pressure of
    2.5 atm from an initial volume of 2.50 L to a final
    volume of 4.50 L. The change in internal energy ΔU
    of the gas in joules will be -
    (1) +505 J
    (2) 1136.25 J
    (3) - 500 J
    (4) - 505 J
    digAnsr:   4
    Ans : (4)
    Sol. ΔU = q + w
    Insulated container So, q = 0
    ΔU = -PdV
    = - 2.5 [4.50 - 2.50]
    = - 2.5 × 2 litre - atm = - 5 l atm [1 -atm = 101.3 ≈ 101J]
    = - 5 × 101
    ⇒ - 505 J
  • Qstn #34
    Correct increasing order for the wavelengths
    of absorption in the visible region for the
    complexes of ``Co^{3+} is -
    (1) ``[Co(NH_3)_6]^{3+}, [Co(en)_3]^{3+}, [Co(H_2O)_6]^{3+}``
    (2) ``[Co(en)_3]^{3+}, [Co(NH_3)_6]^{3+}, [Co(H_2O)_6]^{3+}``
    (3) ``[Co(H_2O)_6]^{3+}, [Co(en)_3]^{3+}, [Co(NH_3)_6]^{3+}``
    (4) ``[Co(H_2O)_6]^{3+}, [Co(NH_3)_6]^{3+}, [Co(en)_3]^{3+}``
    digAnsr:   2
    Ans : (2)
    Sol. Increasing order of wavelength of absorption is
    Δ0 = en > NH3 > H2O
    λ
    ==Δ
    hcE0
    36
    3
    63
    3
    3 ])HO(Co[])NH(Co[])en(Co[
    +++ <<=λ
  • Qstn #35
    The correct statement regarding electrophile is :
    (1) Electrophile can be either neutral or positively
    charged species and can form a bond by accepting a
    pair of electrons from a nucleophile
    (2) Electrophile is a negatively charged species
    and can form a bond by accepting a pair of electrons
    form a nucleophile
    (3) Electrophile is a negatively charged species and
    can form a bond by accepting a pair of electrons
    from another electrophile
    (4) Electrophiles are generally neutral species
    and can form a bond by accepting a pair of electrons from a nucleophile
    digAnsr:   1
    Ans : (1)
    Sol. Electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of
    electrons from a nucleophile.
  • Qstn #36
    For a given reaction, ΔH = 35.5 kJ ``mol^{-1} and
    ΔS = 83.6 ``JK^{-1} ``mol^{-1} . The reaction is spontaneous
    at : (Assume that ΔH and ΔS do not vary with temperature)
    (1) T > 298 K
    (2) T < 425 K
    (3) T > 425 K
    (4) All temperatures
    digAnsr:   3
    Ans : (3)
    Sol. ΔG = ΔH - TΔS
    at equilibrium ΔG = 0
    35.5 × 103 - T × 83.6 = 0
    Teq = 6.83
    105.35 3× = 424.64
    If T > Teq ; ΔG = -ve
    ∴ T > 425 K
  • Qstn #37
    Which of the following pairs of compounds is
    isoelectronic and isostructural ?
    (1)`` IF_3, XeF_2``
    (2) ``BeCl_2, XeF_2``
    (3) ``TeI_2, XeF_2``
    (4) ``IBr_2, XeF_2``
    digAnsr:   4
    Ans : (4)
    Sol. IBr2- and XeF2 are isoelectronic because they conation same number of valence electron and both are linear.
    I Br2 - sp3d linear
    Br
    Br
    I
    -
    Xe F2 sp3d linear
    F
    F
    Xe
    -






  • Qstn #38
    ``HgCl_2`` and ``I_2`` both when dissolved in water containing ``I^-``
    ions pair of species formed is :
    (1) ``Hg_2I_2``, ``I^-``
    (2)`` HgI_2``,`` I_3^-``
    (3) ``HgI_2`` , ``I^-``
    (4)``HgI_4^{2-}`` ,`` I_3^-``
    digAnsr:   4
    Ans : (4)
    Sol. Due to formation of complex
    HgCl2 ⎯→⎯
    -I2 HgI2 ⎯→⎯
    -I2 [HgI4]-2
    I2 ⎯→⎯
    -I -3I
  • Qstn #39
    Which one of the following statements is not correct ?
    (1) Coenzymes increase the catalytic activity of enzyme
    (2) Catalyst does not initiate and reaction
    (3) The value of equilibrium constant is changed in the
    presence of a catalyst in the reaction at equilibrium
    (4) Enzymes catalyse mainly bio-chemical reaction.
    digAnsr:   3
    Ans : (3)
    Sol. Equilibrium constant does not depend on catalyst.
  • Qstn #40
    Ionic mobility of which of the following alkali
    metal ions is lowest when aqueous solutions of their
    salts are put under an electric filed?
    (1) Li
    (2) Na
    (3) K
    (4) Rb
    digAnsr:   4
    Ans : (4)
    Sol. According to electrochemistry due to presence of electric field hydration of ions will not place in excess
    means it effect will be negligible then only ionic weight is the factor.
    Ionic weight of rubidium is high so its mobility will be less.
  • Qstn #41
    The element Z = 114 has been discovered recently.
    It will belong to which of the following family/group
    and electronic configuration ?
    (1) Nitrogen family, [Rn] ``5f^{14}`` ``6d^{10}`` ``7s^2`` ``7p^6``
    (2) Halogen family, [Rn] ``5f^{14}`` ``6d^{10}`` ``7s^2`` ``7p^5``
    (3) Carbon family, [Rn] ``5f^{14}`` ``6d^{10}`` ``7s^2`` ``7p^2``
    (4) Oxygen family, [Rn] ``5f^{14}`` ``6d^{10}`` ``7s^2`` ``7p^4``
    digAnsr:   3
    Ans : (3)
    Sol. Z = 114
    Z114 = [Rn] 5f146d107s27p2
    valence configuration is ns2np2 so Z114 belong to carbon family.







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  • Qstn #42
    Which one is the correct order of acidity ?
    (1) CH3 - CH3 > CH2 = CH2 > CH3 - C ≡ CH > CH≡CH
    (2) CH2 = CH2 > CH3 - CH = CH2 > CH3 - C ≡ CH > CH ≡ CH
    (3) CH ≡ CH > CH3 - C ≡ CH > CH2 = CH2 > CH3 - CH3
    (4) CH ≡ CH > CH2 = CH2 > CH3 - C ≡ CH > CH3 - CH3
    digAnsr:   3
    Ans : (3)
    Sol. Acidic nature ∝
    I
    I
    +
    - ∝ E. N.
    ∴ Acidic strength order will be
    EN(sp carbon) = 3.25 EN(sp2 carbon)
    = 2.75
    EN(sp3 carbon)
    = 2.50
    HC ≡ CH > CH3 - C ≡ CH > CH2 = CH2 > CH3 - CH3
  • Qstn #43
    If molality of the dilute solution is doubled,
    the value of molal depression constant (``K_f``) will be
    (1) unchanged
    (2) doubled
    (3) halved
    digAnsr:   1
    Ans : (1)
    Sol. ΔTf = Kf × m
    Kf → does not depend on molality
    So, Kf molal depression constant remains same
  • Qstn #44
    The species, having bond angles of 120º is
    (1) ``BCl_3``
    (2) ``PH_3``
    (3) ``CIF_3``
    (4) ``NCl_3``
    digAnsr:   1
    Ans : (1)
    Sol. BCl3 is sp2 hybridized so, BCl3 is trigonal planar and Bond angle is 120º
    Cl
    B
    Cl Cl


  • Qstn #45
    Which of the following reactions is appropriate
    for converting acetamide to methanamine ?
    (1) Gabriels phthalimide synthesis
    (2) Carbylamine reaction
    (3) Hoffmann hypobromamide reaction
    (4) Stephens reaction
    digAnsr:   3
    Ans : (3)
    Sol.
    O
    CH3 - C - NH2
    Br2 + (4) KOH
    Or KOBr CH3 - NH2