NEET-XII-Chemistry

Previous Year Paper year:2017

with Solutions - page 2
  • #29
    Machanism of a hypothetical reaction ``\ce X2+ Y2`` → 2XY is given below.
    ( i) ``X_ 2`` → X + X (fast)
    (ii) X + ``Y_2`` ``\rightleftharpoons`` XY + Y (slow)
    (iii) X + Y → XY (fast)
    The overall order of the reaction will be -
    (1) 1.5
    (2) 1
    (3) 2
    (4) 0
    digAnsr:   1
    Ans : (1)
    Sol. From slow step
    r = k [X] [Y2]
    but [X] is dummy reactant so it will replaced by step I
    ]X[
    ]X[K
    2
    2
    c =
    ]X[K]X[ 2c=
    ∴ 122
    1
    2
    2
    1
    c ]Y[]X[)K(Kr =
    so overall order = 5.11
    2
    1
    =+