Qstnid -Ii-12- How Much Charge Is Required For The Following Reductions: () 1 Mol Of Al<sup>3+</sup> To Al. () 1 Mol Of Cu<sup>2+ </Sup>to Cu. () 1 Mol Of <Img Src="\etl\image\esa-cbse-xii\chem-hwh-sb1\c03/ncert_17-11-08_utpal_12_chemistry_3_18_html_47cc3b45.gif" Width="45" Height="25"> To Mn<sup>2+</sup>. () 1 Mol Of Cu<sup>2+ </Sup>to Cu. () 1 Mol Of <Img Src="\etl\image\esa-cbse-xii\chem-hwh-sb1\c03/ncert_17-11-08_utpal_12_chemistry_3_18_html_47cc3b45.gif" Width="45" Height="25"> To Mn<sup>2+</sup>. - 03: Electrochemistry - Neet-xii-chemistry

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NEET-XII-Chemistry

03: Electrochemistry

page 3

Qstn# II-12 Prvs-Qstn Next-Qstn

#12
How much charge is required for the following reductions:
() 1 mol of Al³⁺ to Al.
() 1 mol of Cu²⁺to Cu.
() 1 mol of to Mn²⁺.
() 1 mol of Cu²⁺to Cu.
() 1 mol of to Mn²⁺.
Ans : null ()

Required charge = 3 F

= 3 × 96487 C

= 289461 C
()

Required charge = 2 F

= 2 × 96487 C

= 192974 C
()

i.e.,

Required charge = 5 F

= 5 × 96487 C

= 482435 C
()

Required charge = 2 F

= 2 × 96487 C

= 192974 C
()

i.e.,

Required charge = 5 F

= 5 × 96487 C

= 482435 C

#12-i
1 mol of Al³⁺ to Al.
() 1 mol of Cu²⁺to Cu.
() 1 mol of to Mn²⁺.
Ans :

Required charge = 3 F

= 3 × 96487 C

= 289461 C
()

Required charge = 2 F

= 2 × 96487 C

= 192974 C
()

i.e.,

Required charge = 5 F

= 5 × 96487 C

= 482435 C

#12-ii
1 mol of Cu²⁺to Cu.
Ans :

Required charge = 2 F

= 2 × 96487 C

= 192974 C

#12-iii
1 mol of to Mn²⁺.
Ans :

i.e.,

Required charge = 5 F

= 5 × 96487 C

= 482435 C