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NEET-XII-Chemistry

02: Solutions

with Solutions - page 2
Qstn# B-8 Prvs-QstnNext-Qstn
  • #8
    An
    antifreeze solution is prepared from 222.6 g of ethylene glycol
    (C2H6O2)
    and 200 g of water. Calculate the molality of the solution. If the
    density of the solution is 1.072 g mL-1,
    then what shall be the molarity of the solution?
    Ans : Molar mass of ethylene
    glycol=
    2 × 12 + 6 × 1 + 2 ×16
    = 62 gmol-1
    Number of moles of
    ethylene glycol
    = 3.59 mol
    Therefore, molality of
    the solution
    = 17.95 m
    Total mass of the
    solution = (222.6 + 200) g
    = 422.6 g
    Given,
    Density of the solution
    = 1.072 g mL-1
    Volume
    of the solution
    = 394.22 mL
    = 0.3942 × 10-3 L
    Molarity of the solution
    = 9.11 M