ICSE-VIII-Mathematics
17: Special Types of Quadrilaterals Class 8 Maths
- #7ABCD is a rhombus. If ∠BCA = 35°. find ∠ADC.Ans : Given: Rhombus ABCD in which ∠BCA = 35°
To find : ∠ADC
Proof : AD || BC
∠DAC = ∠BCA (Alternate ∠s)
But ∠BCA = 35° (Given)
∠DAC = 35°
But ∠DAC = ∠ACD (AD = CD)& ∠DAC +∠ACD + ∠ADC = 180°
⇒ 35° + 35° + ∠ADC = 180°
⇒ ∠ADC = 180° - 70° = 110°
Hence, ∠ADC = 110°