NEET-XII-Physics
32: Electric Current in Conductors
- #35Each of the resistors shown in the figure (32-E11) has a resistance of 10 Ω and each of the batteries has an emf of 10 V. Find the currents flowing through the resistors a and b in the two circuits.
figure 32-E11
Ans : (a)
From the figure,
Potential difference between the two ends of resistor a = 10 V
Resistance of resistor a =10 Ω
∴ Current through a = `` \frac{10}{10}=1\,\mathrm{\,A\,}``
Since the two batteries are connected opposite each other,
potential difference between the terminals of b = 10 - 10 = 0 V
∴ Current through b = 0 A
(b)
From the figure,
Potential difference between the two ends of resistor a = 10 V.
Resistance of resistor a =10 Ω
∴ Current through a = `` \frac{10}{10}=1\,\mathrm{\,A\,}``
Since the two batteries are again connected opposite to each other,
Potential difference between terminal of b = 10 - 10 = 0 V
∴ Current through b = 0 A
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