NEET-XII-Physics
neet 2020 questions with solutions year:2020
- #27The average thermal energy for a mono-atomic gas is : ( `` k_B `` is Boltzmann constant and T, absolute temperature)
(A) `` \frac {1}{2} k_BT ``
(B) `` \frac {3}{2} k_BT ``
(C) `` \frac {5}{2} k_BT ``
(D) `` \frac {7}{2} k_BT ``
digAnsr: BAns : Average thermal energy `` =\frac{3}{2}K_{B}T ``
(where 3 is translational degree of freedom)
For monoatomic gas total degree of freedom
`` f= 3 `` (translational degree of freedom)