NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #24
    A particle of mass 10 g moves along a circle of
    radius 6.4 cm with a constant tangential
    acceleration. What is the magnitude of this
    acceleration if the kinetic energy of the particle
    becomes equal to 8 × ``10^{-4}`` J by the end of the
    second revolution after the beginning of the
    motion?
    (1) 0.1 ``\frac {m}{s^2}``(2) 0.15 ``\frac {m}{s^2}``
    (3) 0.18 ``\frac {m}{s^2}`` (4) 0.2 ``\frac {m}{s^2}``
    digAnsr:   1
    Ans : 1
    Sol. 2
    1
    mv
    2
    = E &implies;
     
     
     
    21 10 v
    2 1000
    = 8 × 10-4
    &implies; v2 = 16 × 10-2 &implies; v = 4 × 10-1 = 0.4 m/s
    Now,
    v2 = u2 + 2ats (s = 4R)
    &implies;
     
    = +   
     
    2
    t
    16 22 6.4
    0 2a 4
    100 7 100
    &implies; at =


     
    16 7 100
    100 8 22 6.4
    = 0.1 m/s2