NEET-XII-Physics
exam-1 year:2016
- #25The molecules of a given mass of a gas
have r.m.s. velocity of 200 ``\frac {m}{s}`` at 27°C and
1.0 × ``10^5 Nm^{-2}`` pressure. When the temperature
and pressure of the gas are respectively, 127°C and
0.05 × 105 ``10^5 Nm^{-2}``, the r.m.s. velocity of
its molecules in ``ms^{-1}`` is :
(1) 100 ``\sqrt 2``
(2)``\frac {400}{\sqrt 3}``
(3)``\frac {100\sqrt 2 }{3}``
(4) 100/3digAnsr: 2Ans : 2
Sol. v T &implies; =
v 400
200 300
&implies; v =
200 2
3
m/s
&implies; v =
400
3
m/s