NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #25
    The molecules of a given mass of a gas
    have r.m.s. velocity of 200 ``\frac {m}{s}`` at 27°C and
    1.0 × ``10^5 Nm^{-2}`` pressure. When the temperature
    and pressure of the gas are respectively, 127°C and
    0.05 × 105 ``10^5 Nm^{-2}``, the r.m.s. velocity of
    its molecules in ``ms^{-1}`` is :
    (1) 100 ``\sqrt 2``
    (2)``\frac {400}{\sqrt 3}``
    (3)``\frac {100\sqrt 2 }{3}``
    (4) 100/3
    digAnsr:   2
    Ans : 2
    Sol. v  T &implies; =
    v 400
    200 300
    &implies; v =
    200 2
    3
    m/s
    &implies; v =
    400
    3
    m/s