NEET-XII-Physics

exam-1 year:2016

with Solutions - page 2
  • #23
    When an ``\alpha``-particle of mass 'm' moving
    with velocity 'v' bombards on a heavy nucleus of
    charge 'Ze', its distance of closest approach from the nucleus
    depends on m as :
    (1) 1/m
    (2) ``\frac {1}{\sqrt m}``
    (3) ``\frac {1}{m^2}``
    (4) m
    digAnsr:   1
    Ans : 1
    Sol. At closest distance of approach, the kinetic energy
    of the particle will convert completely into
    electrostatic potential energy.
    &implies; =
    21 KQqmv
    2 d
    &implies; d 
    1
    m