NEET-XII-Physics
exam-1 year:2016
- #23When an ``\alpha``-particle of mass 'm' moving
with velocity 'v' bombards on a heavy nucleus of
charge 'Ze', its distance of closest approach from the nucleus
depends on m as :
(1) 1/m
(2) ``\frac {1}{\sqrt m}``
(3) ``\frac {1}{m^2}``
(4) mdigAnsr: 1Ans : 1
Sol. At closest distance of approach, the kinetic energy
of the particle will convert completely into
electrostatic potential energy.
&implies;ï€ =
21 KQqmv
2 d
&implies; d 
1
m