NEET-XII-Chemistry

Previous Year Paper year:2017

with Solutions - page 4

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  • Qstn #46
    The number of sigma (``\sigma``) and pi (``\pi``) bonds in
    pent-2-en-4-yne is
    (1) 10 ``\sigma`` bonds and 3``\pi`` bonds
    (2) 8 ``\sigma``bonds and 5``\pi`` bonds
    (3) 11 ``\sigma`` bonds and 2``\pi`` bonds
    (4) 13``\sigma`` bonds and no ``\pi`` bonds
    digAnsr:   1
    Ans : ( 1 )
    Sol. H - C - C = C - C C - H
    H
    H H
    H



      
     

    Number of  bonds = 10
    and number of  bonds = 3
  • Qstn #47
    The structure of intermediate A in the
    following reaction, is
    m47.png
    (1) m47a.png
    (2) m47b.png
    (3) m47c.png
    (4) m47d.png
    digAnsr:   4
    Ans : ( 4 )

    Sol.
    CH
    CH
    3
    CH
    3
    O2 H
    +
    H O2
    OH
    + H C - C -CH3 3
    O
    H C - C - O - O - H3
    CH
    3
    (A)
    Cumene
    hydroperoxide
    Cumene
  • Qstn #48
    The correct structure of tribromooctaoxide is
    (1) m48a.png
    (2) m48b.png
    (3) m48c.png
    (4) m48d.png
    digAnsr:   1
    Ans : ( 1 )
    Sol. The correct structure is
    O = Br - Br - Br = O
    O
    O
    O
    O
    O
    O
    Tribromooctaoxide
  • Qstn #49
    4d, 5p, 5f and 6p orbitals are arranged in the
    order of decreasing energy. The correct
    option is
    (1) 5f > 6p > 5p > 4d
    (2) 6p > 5f > 5p > 4d
    (3) 6p > 5f > 4d > 5p
    (4) 5f > 6p > 4d > 5p
    digAnsr:   1
    Ans : ( 1 )
    Sol. (n + l) values for, 4d = 4 + 2 = 6
    5p = 5 + 1 = 6
    5f = 5 + 3 = 8
    6p = 6 + 1 = 7
    ∴ Correct order of energy would be
    5f > 6p > 5p > 4d
  • Qstn #50
    Which of the following reactions are
    disproportionation reaction?
    (a )`` 2Cu^+ \longrightarrow`` ``Cu^{2+} + Cu^0``
    (b)``3MnO_4^{2-} + 4H^+ \longrightarrow`` ``2MnO_4^- + MnO_2 + 2H_2O``
    (c)\begin{aligned}
    & \ce{$2KMnO_4 $ ->[\ce{\triangle}] $K_2MnO_4 + MnO_2 + 0_2$}
    \end{aligned}
    (d)``2MnO_4 ^- + 3Mn^{2+} + 2H_2O \longrightarrow`` ``5MnO_2 + 4H^+``
    Select the correct option from the following
    (1) (a) and (b) only
    (2) (a), (b) and (c)
    (3) (a), (c) and (d)
    (4) (a) and (d) only
    digAnsr:   1
    Ans : ( 1 )
    Sol. (a)
    +
    + 
    1
    1
    2Cu
    +
    + +
    2 0
    2( ) 0
    Cu Cu } Disproportionation
    (b)
    +
     ++ 
    6
    2( ) ( )
    43MnO 4H
    + +
     + +
    7 4
    4 2 2
    2MnO MnO 2H O}Disproportionation
    (c)
    + +
    ▵  +
    7 6
    2
    4 2 4
    2KMnO K MnO
    +
    + ∴
    4 0
    2 2
    MnO O } Not a disproportionation
    (d)
    + +
     ++ + 
    7 2
    2( )
    4 22MnO 3Mn 2H O
    +
    +
    4
    2
    5MnO 4H }
    14
  • Qstn #51
    Under isothermal condition, a gas at 300 K
    expands from 0.1 L to 0.25 L against a
    constant external pressure of 2 bar. The work
    done by the gas is
    (Given that 1 L bar = 100 J)
    (1) -30 J (2) 5 kJ
    (3) 25 J (4) 30 J
    digAnsr:   1
    Ans : ( 1 )
    Sol. ∴ W
    irr
    = - P
    ext
    ▵V
    = - 2 bar × (0.25 - 0.1) L
    = - 2 × 0.15 L-bar
    = - 0.30 L-bar
    = - 0.30 × 100 J
    = - 30 J
  • Qstn #52
    Among the following, the one that is not a
    green house gas is
    (1) Nitrous oxide (2) Methane
    (3) Ozone (4) Sulphur dioxide
    digAnsr:   4
    Ans : ( 4 )
    Sol. Fact
    SO
    2
    (g) is not a greenhouse gas.
  • Qstn #53
    For the cell reaction
    ``2Fe^{3+}(aq) + 2I^- (aq) ````\longrightarrow`` ``2Fe^{2+}(aq) + I_2 (aq) ``
    ``E_{CELL}^\circleddash ``= 0.24 V at 298 K. The standard Gibbs
    energy (``\triangle_rG^\circleddash ``)of the cell reaction is :
    [Given that Faraday constant F = 96500 C `` mol^{-1}``]
    (1) - 46.32 kJ `` mol^{-1}`` (2) - 23.16 kJ `` mol^{-1}``
    (3) 46.32 kJ `` mol^{-1}`` (4) 23.16 kJ `` mol^{-1}``
    digAnsr:   1
    Ans : ( 1 )
    Sol.
    Θ Θ▵ 
    cell
    G = nF E
    = - 2 × 96500 × 0.24 J mol-1
    = - 46320 J mol-1
    = - 46.32 kJ mol-1
  • Qstn #54
    Enzymes that utilize ATP in phosphate transfer
    require an alkaline earth metal (M) as the
    cofactor. M is :
    (1) Be (2) Mg
    (3) Ca (4) Sr
    digAnsr:   2
    Ans : ( 2 )
    Sol. All enzymes that utilize ATP in phosphate
    transfer require magnesium(Mg) as the
    co-factor.
  • Qstn #55
    The most suitable reagent for the following
    conversion, is :
    m55.png
    (1) Na/liquid ``NH_3``
    (2) ``H_2``, Pd/C, quinoline
    (3) Zn/HCl
    (4) ``Hg^{2+}/H^+, H_2O``
    digAnsr:   2
    Ans : ( 2 )
    Sol. H C C C CH3 3
    CH
    3
    H
    H C
    3
    H
    cis-2-butene
    H , Pd/C,2
    quinoline
    C C
  • Qstn #56
    Which is the correct thermal stability order
    for ``H_2E ``(E = O, S, Se, Te and Po)?
    (1)`` H_2S < H_2O < H_2Se < H_2Te < H_2Po``
    (2)`` H_2O < H_2S < H_2Se < H_2Te < H_2Po``
    (3)`` H_2Po < H_2Te < H_2Se < H_2S < H_2O``
    (4) ``H_2Se < H_2Te < H_2Po < H_2O < H_2S``
    digAnsr:   3
    Ans : ( 3 )
    Sol. On going down the group thermal stability
    order for H
    2
    E decreases because H-E bond
    energy decreases
    ∴ Order of stability would be:-
    H
    2
    Po < H
    2
    Te < H
    2
    Se < H
    2
    S < H
    2
    O
  • Qstn #57
    Which of the following is incorrect statement?
    (1)`` PbF_4`` is covalent in nature
    (2) ``SiCl_4`` is easily hydrolysed
    (3) ``GeX_4``(X = F, Cl, Br, I) is more stable than
    ``GeX_2``
    (4)`` SnF_4`` is ionic in nature.
    digAnsr:   1
    Ans : ( 1 )
    Sol. PbF
    4
    and SnF
    4
    are ionic in nature.
  • Qstn #58
    Match the following :
    (a ) Pure nitrogen (i) Chlorine
    (b) Haber process (ii) Sulphuric acid
    (c) Contact process (iii) Ammonia
    (d) Deacon’s process (iv) Sodium azide or Barium azide
    Which of the following is the correct option?
    (a ) (b) (c) (d)
    (1) (i) (ii) (iii) (iv)
    (2) (ii) (iv) (i) (iii)
    (3) (iii) (iv) (ii) (i)
    (4) (iv) (iii) (ii) (i)
    digAnsr:   4
    Ans : ( 4 )
    Sol. (a) Pure nitrogen : Sodium azide or
    Barium azide
    (b) Haber process : Ammonia
    (c) Contact process : Sulphuric acid
    (d) Deacon’s process : Chlorine
  • Qstn #59
    Which of the following diatomic molecular
    species has only ``\PI`` bonds according to
    Molecular Orbital Theory?
    (1) ``O_2``
    (2)`` N_2``
    (3)`` C_2``
    (4) ``Be_2``
    digAnsr:   3
    Ans : ( 3 )
    Sol. MO configuration C
    2
    is:
    1s2, *1s2, 2s2, *2s2,  = 2 2x y2p 2p
  • Qstn #60
    For the second period elements the correct
    increasing order of first ionisation enthalpy is:
    (1) Li < Be < B < C < N < O < F < Ne
    (2) Li < B < Be < C < O < N < F < Ne
    (3) Li < B < Be < C < N < O < F < Ne
    (4) Li < Be < B < C < O < N < F < Ne
    digAnsr:   2
    Ans : ( 2 )
    Sol. ‘Be’ and ‘N’ have comparatively more stable
    valence sub-shell than ‘B’ and ‘O’.
    ∴ Correct order of first ionisation enthalpy
    is:
    Li < B < Be < C < O < N < F < Ne