NEET-XII-Chemistry
Previous Year Paper year:2017
- #53For the cell reaction
``2Fe^{3+}(aq) + 2I^- (aq) ````\longrightarrow`` ``2Fe^{2+}(aq) + I_2 (aq) ``
``E_{CELL}^\circleddash ``= 0.24 V at 298 K. The standard Gibbs
energy (``\triangle_rG^\circleddash ``)of the cell reaction is :
[Given that Faraday constant F = 96500 C `` mol^{-1}``]
(1) - 46.32 kJ `` mol^{-1}`` (2) - 23.16 kJ `` mol^{-1}``
(3) 46.32 kJ `` mol^{-1}`` (4) 23.16 kJ `` mol^{-1}``digAnsr: 1Ans : ( 1 )
Sol.
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cell
G = nF E
= - 2 × 96500 × 0.24 J mol-1
= - 46320 J mol-1
= - 46.32 kJ mol-1