NEET-XII-Chemistry

Previous Year Paper year:2017

with Solutions - page 4
  • #53
    For the cell reaction
    ``2Fe^{3+}(aq) + 2I^- (aq) ````\longrightarrow`` ``2Fe^{2+}(aq) + I_2 (aq) ``
    ``E_{CELL}^\circleddash ``= 0.24 V at 298 K. The standard Gibbs
    energy (``\triangle_rG^\circleddash ``)of the cell reaction is :
    [Given that Faraday constant F = 96500 C `` mol^{-1}``]
    (1) - 46.32 kJ `` mol^{-1}`` (2) - 23.16 kJ `` mol^{-1}``
    (3) 46.32 kJ `` mol^{-1}`` (4) 23.16 kJ `` mol^{-1}``
    digAnsr:   1
    Ans : ( 1 )
    Sol.
    Θ Θ▵ 
    cell
    G = nF E
    = - 2 × 96500 × 0.24 J mol-1
    = - 46320 J mol-1
    = - 46.32 kJ mol-1