NEET-XII-Chemistry
exam-2 year:2016
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- Qstn #150The correct corresponding order names of four
aldoses with configuration given below

respectively, is :-
(1) L-erythrose, L-threose, D-erythrose, D-threose
(2) D-erythrose, D-threose, L-erythrose, L-threose
(3) L-erythrose, L-threose, L-erythrose, D-threose
(4) D-threose, D-erythrose, L-threose, L-erythrosedigAnsr: 2Ans : (2)
Sol.
CHO
OHH
OHH
CH2 OH
D-Erythrose
CHO
HOH
OHH
CH2 OH
D-Threose
CHO
HOH
HOH
CH2 OH
L-Erythrose
CHO
OHH
HOH
CH2 OH
L-Threose
- Qstn #151In the given reaction

the product P is :-
(1)
(2)
(3)
(4)
digAnsr: 1Ans : (1)
Sol.
H
+
(HF)
Carbocation
H
ESR
(alkylation)+
[Friedel Craft reaction]
- Qstn #152A given nitrogen-containing aromatic compound A
reacts with Sn/HCl, followed by ``HNO_2`` to give an
unstable compound B. B, on treatment with phenol,
forms a beatiful coloured compound C with the
molecular formula ``C_{12}H_{10}N_2O``.
The structure of compound A is :-
(1)
(2)
(3)
(4)
digAnsr: 4Ans : (4)
Sol.
NO2
(A)
NH2
Aniline
N2·Cl
N N OH
Sn+HCl
Reduction
HNO2
Ph—OH
(B)
Benzene Diazonium
chloride
p-Hydroxy azo benzene (red colour dye)
- Qstn #153Consider the reaction
``\ce {CH3CH2CH2Br + NaCN \rightarrow CH3CH2CH2CN + NaBr}``
This reaction will be the fastest in
(1) N,N'-dimethylformamide (DMF)
(2) water
(3) ethanol
(4) methanoldigAnsr: 1Ans : (1)
Sol. CH3-CH2-CH2Br + NaCN CH3CH2CH2CN+
NaBr
This reaction follows by SN2 path, which is favoured
by polar aprotic solvents like DMF, DMSO, etc.
DMF (Dimethyl formamide)
H C
O
N
Me
Me
- Qstn #154The correct structure of the product A formed in
the reaction

(1)
(2)
(3)
(4)
digAnsr: 4Ans : (4)
Sol.
O
2H gas, (1 atmosphere)
Pd/Carbon,Ethanol
O
- Qstn #155Which among the given molecules can exhibit
tautomerism ?

(1) Both I and II
(2) Both II and III
(3) III only
(4) Both I and IIIdigAnsr: 3Ans : (3)
Sol.
O
H
H
Keto form
OH
Enol
- Qstn #156The correct order of strengths of the carboxylic acids

is
(1) III > II > I
(2) II > I > III
(3) I > II > III
(4) II > III > IdigAnsr: 4Ans : (4)
Sol. Acidic Strength
O
COOH
more(—I)
>
O
COOH COOH
(+I)
>
less (—I)
- Qstn #157The compound that will react most readily with
gaseous bromine has the formula
(1) ``C_4H_{10}``
(2) ``C_2H_4``
(3) ``C_3H_6``
(4) ``C_2H_2``digAnsr: 3Ans : (3)
Sol. Gaseous Bromine reacts with alkene to give allylic
substituted product by free radical mechanism
CH3-CH=CH2 2Br gas CH2 CH
CH2
Br
- Qstn #158Which one of the following compounds shows the
presence of intramolecular hydrogen bond ?
(1) Cellulose
(2) Concentrated acetic acid
(3) ``H_2O_2``
(4) HCNdigAnsr: 1Ans : (1)
Sol. In acetic acid, H2O2 and HCN inter molecular
hydrogen bond present but in cellulose
intramolecular hydrogen bond present.
- Qstn #159The molar conductivity of a 0.5 mol/``dm^3``
solution of ``AgNO_3`` with electrolytic conductivity of
5.76 × ``10^{-3} S cm^{-1}`` at 298 K is
(1) 0.086 S ``cm^2/mol``
(2) 28.8 S ``cm^2/mol``
(3) 2.88 S ``cm^2/mol``
(4) 11.52 S ``cm^2/mol``digAnsr: 4Ans : (4)
Sol. C = 0.5 mol / dm3
= 5.76 × 10-3 S cm-1
T = 298 K
= = =
3
m
1000 5.76 10
11.52
M 0.5
Scm2/mol
- Qstn #160The decomposition of phosphine (``PH_3``) on tungsten
at low pressure is a first-order reaction. It is because
the
(1) rate is independent of the surface coverage
(2) rate of decomposition is very slow
(3) rate is proportional to the surface coverage
(4) rate is inversely proportional to the surface
coveragedigAnsr: 3Ans : (3)
Sol. The decomposition of PH3 on tungsten at low
pressure is a first order reaction because rate is
proportional to the surface coverage.
- Qstn #161The coagulation values in millimoles per litre of the
electrolytes used for the coagulation of ``As_2S_3`` are
given below :
I. (NaCl) = 52, II. (``BaCl_2``) = 0.69,
III. (``MgSO_4``) = 0.22
The correct order of their coagulating power is
(1) III > II > I
(2) III > I > II
(3) I > II > III
(4) II > I > IIIdigAnsr: 1Ans : (1)
Sol. Coagulation power
1
coagulation value
So, the order is III > II > I
- Qstn #162During the electrolysis of molten sodium chloride,
the time required to produce 0.10 mol of chlorine
gas using a current of 3 amperes is
(1) 220 minutes
(2) 330 minutes
(3) 55 minutes
(4) 110 minutesdigAnsr: 4Ans : (4)
Sol. +22Cl Cl g 2e
=
E
W it
96500
=
35.5
0.1 71 3 t(sec)
96500
t (s) = 6433.33 sec
t(min) = 107.22 min 110 min.
- Qstn #163How many electrons can fit in the orbital for which
n = 3 and l = 1 ?
(1) 10
(2) 14
(3) 2
(4) 6digAnsr: 3Ans : (3)
Sol. n=3, l =1 &implies;3p
Total 2 electron can fit in the orbital of 3p
- Qstn #164For a sample of perfect gas when its pressure is
changed isothermally from ``p_i`` to ``p_f``, the
entropy change is given by
(1)``\triangle S`` = nRT `` ln \frac {p_f}{p_i}``
(2)``\triangle S`` = RT `` ln \frac {p_i}{p_f}``
(3)``\triangle S`` = nR `` ln \frac {p_f}{p_i}``
(4)``\triangle S`` = nR `` ln \frac {p_i}{p_f}``digAnsr: 4Ans : (4)
Sol. ▵ = +
f i
pm
i f
T P
S nC n nR n
T P
For isothermal Ti = Tf, ln1 = 0
▵ = i
f
P
S nR n
P