NEET-XII-Physics
13: Nuclei
- #30Calculate and compare the energy released by a) fusion of 1.0 kg of hydrogen deep within Sun and b) the fission of 1.0 kg of 235U in a fission reactor.
Ans : a) Amount of hydrogen, m = 1 kg = 1000 g
1 mole, i.e., 1 g of hydrogen (
) contains 6.023 × 1023 atoms.
∴1000 g of contains 6.023 × 1023 × 1000 atoms.
Within the sun, four nuclei combine and form one .gif)
nucleus. In this process 26 MeV of energy is released.
Hence, the energy released from the fusion of 1 kg
is:
b) Amount of
= 1 kg = 1000 g
1 mole, i.e., 235 g of contains 6.023 × 1023 atoms.
∴1000 g ofcontains 
It is known that the amount of energy released in the fission of one atom ofis 200 MeV.
Hence, energy released from the fission of 1 kg of is:
∴
Therefore, the energy released in the fusion of 1 kg of hydrogen is nearly 8 times the energy released in the fission of 1 kg of uranium.