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NEET-XII-Physics

11: Dual Nature Of Radiation And Matter

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  • #3
    The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
    Ans : Photoelectric cut-off voltage, V0 = 1.5 V

    The maximum kinetic energy of the emitted photoelectrons is given as:



    Where,

    e = Charge on an electron = 1.6 × 10-19 C



    Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 × 10-19 J.