HomeLearn Fast select Course
Change UnitChange SubjectLast Menu
NEET-XI-Chemistry

06: Hydrocarbons

Note: Please signup/signin free to get personalized experience.

Note: Please signup/signin free to get personalized experience.

10 minutes can boost your percentage by 10%

No item to list.

Note: Please signup/signin free to get personalized experience.

  
  • #
    Chapter 6 - Hydrocarbons
  • Qstn #1
    How do you account for the formation of ethane during chlorination of methane?
    Ans : Chlorination of methane proceeds via a free radical chain mechanism. The whole reaction takes place in the given three steps.

    Step 1: Initiation:

    The reaction begins with the homolytic cleavage of Cl - Cl bond as:



    Step 2: Propagation:

    In the second step, chlorine free radicals attack methane molecules and break down the C-H bond to generate methyl radicals as:



    These methyl radicals react with other chlorine free radicals to form methyl chloride along with the liberation of a chlorine free radical.



    Hence, methyl free radicals and chlorine free radicals set up a chain reaction. While HCl and CH3Cl are the major products formed, other higher halogenated compounds are also formed as:



    Step 3: Termination:

    Formation of ethane is a result of the termination of chain reactions taking place as a result of the consumption of reactants as:



    Hence, by this process, ethane is obtained as a by-product of chlorination of methane.
  • Qstn #2
    Write IUPAC names of the following compounds:
  • #2-a

    Ans :

    IUPAC name: 2-Methylbut-2-ene
  • #2-b

    Ans :

    IUPAC name: Pen-1-ene-3-yne
  • #2-c

    Ans : can be written as:



    IUPAC name: 1, 3-Butadiene or Buta-1,3-diene
  • #2-d

    Ans :

    IUPAC name: 4-Phenyl but-1-ene
  • #2-e

    Ans :

    IUPAC name: 2-Methyl phenol
  • #2-f

    Ans :

    IUPAC name: 5-(2-Methylpropyl)-decane
  • #2-g

    Ans :

    IUPAC name: 4-Ethyldeca-1, 5, 8-triene
  • Qstn #3
    For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bond as indicated:
  • #3-a
    C4H8 (one double bond)
    Ans : The following structural isomers are possible for C4H8 with one double bond:







    The IUPAC name of

    Compound (I) is But-1-ene,

    Compound (II) is But-2-ene, and

    Compound (III) is 2-Methylprop-1-ene.
  • #3-b
    C5H8 (one triple bond)
    Ans : The following structural isomers are possible for C5C8 with one triple bond:







    The IUPAC name of

    Compound (I) is Pent-1-yne,

    Compound (II) is Pent-2-yne, and

    Compound (III) is 3-Methylbut-1-yne.
  • Qstn #4
    Write IUPAC names of the products obtained by the ozonolysis of the following compounds:
  • Qstn #4-i
    Pent-2-ene
    Ans : Pent-2-ene undergoes ozonolysis as:



    The IUPAC name of Product (I) is ethanal and Product (II)is propanal.
next page