Qstnid -A-2- Calculate The Sum Of Angles Of A Polygon With : (I) 10 Sides (Ii) 12 Sides (Iii) 20 Sides (Iv) 25 Sides (I) 10 Sides (Ii) 12 Sides (Iii) 20 Sides (Iv) 25 Sides - 16: Understanding Shapes (Including Polygons) Class 8 Maths - Icse-viii-mathematics

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ICSE-VIII-Mathematics

16: Understanding Shapes (Including Polygons) Class 8 Maths

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Qstn# A-2 Prvs-Qstn Next-Qstn

#2
Calculate the sum of angles of a polygon with : (i) 10 sides (ii) 12 sides (iii) 20 sides (iv) 25 sides (i) 10 sides (ii) 12 sides (iii) 20 sides (iv) 25 sides
Ans : (i) No. of sides n = 10
sum of angles of polygon = (n - 2)×180°
= (10 - 2)× 180° = 1440° (ii) no. of sides n = 12
sum of angles = (n - 2)×180°
= (12 - 2)×180° = 10×180° = 1800° (iii) n = 20
Sum of angles of Polygon = (n - 2)× 180°
= (20 - 2)× 180° = 3240° (iv) n = 25
Sum of angles of polygon = (n - 2)× 180°
= (25 - 2)× 180° = 4140° (i) No. of sides n = 10
sum of angles of polygon = (n - 2)×180°
= (10 - 2)× 180° = 1440° (ii) no. of sides n = 12
sum of angles = (n - 2)×180°
= (12 - 2)×180° = 10×180° = 1800° (iii) n = 20
Sum of angles of Polygon = (n - 2)× 180°
= (20 - 2)× 180° = 3240° (iv) n = 25
Sum of angles of polygon = (n - 2)× 180°
= (25 - 2)× 180° = 4140°

#2-i
10 sides
Ans : No. of sides n = 10
sum of angles of polygon = (n - 2)×180°
= (10 - 2)× 180° = 1440°

#2-ii
12 sides
Ans : no. of sides n = 12
sum of angles = (n - 2)×180°
= (12 - 2)×180° = 10×180° = 1800°

#2-iii
20 sides
Ans : n = 20
Sum of angles of Polygon = (n - 2)× 180°
= (20 - 2)× 180° = 3240°

#2-iv
25 sides
Ans : n = 25
Sum of angles of polygon = (n - 2)× 180°
= (25 - 2)× 180° = 4140°