ICSE-VIII-Mathematics
16: Understanding Shapes (Including Polygons) Class 8 Maths
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- #Section : A
- Qstn #1State which of the following are polygons:
If the given figure is a polygon, name it as convex or concave.Ans : Only Fig. (ii), (iii) and (v) are polygons.
Fig. (ii) and (iii) are concave polygons while
Fig. (v) is convex.
- #2-i10 sidesAns : No. of sides n = 10
sum of angles of polygon = (n - 2)×180°
= (10 - 2)× 180° = 1440°
- #2-ii12 sidesAns : no. of sides n = 12
sum of angles = (n - 2)×180°
= (12 - 2)×180° = 10×180° = 1800°
- #2-iii20 sidesAns : n = 20
Sum of angles of Polygon = (n - 2)× 180°
= (20 - 2)× 180° = 3240°
- #2-iv25 sidesAns : n = 25
Sum of angles of polygon = (n - 2)× 180°
= (25 - 2)× 180° = 4140°
- #3-i900°Ans : Let no. of sides = n
Sum of angles of polygon = 900˚(n - 2) × 180˚ = 900˚
⇒ n - 2 = 900/180
⇒ n - 2 = 5
⇒ n = 5 + 2
⇒ n = 7
- #3-ii1620°Ans : Let no. of sides = n
Sum of angles of polygon = 1620Ëš
(n - 2) × 180˚ = 1620˚
⇒ n - 2 = 1620/180
⇒ n - 2 = 9
⇒ n = 9 + 2
⇒ n = 11
- #3-iii16 right-anglesAns : Let no. of sides = n
Sum of angles of polygon = 16 right = 16 × 90 = 1440˚
(n - 2) × 180˚ = 1440˚
⇒ n - 2 = 1440/180˚
⇒ n - 2 = 8
⇒ n = 8 + 2
⇒ n = 10
- #3-iv32 right-angles.Ans : Let no. of sides = n
Sum of angles of polygon = 32 right angles = 32 × 90 = 2880˚
(n × 2) × 180˚ = 2880
n - 2 = 2880/180
n - 2 = 16
n = 16 + 2
n =18
- #4-i870°Ans : Let no. of sides = n
Sum of angles = 870°
(n - 2) × 180° = 870°
⇒ n - 2 = 870/180
⇒ n - 2 = 29/6
⇒ n = 29/6 + 2
⇒ n = 41/6
Which is not a whole number.
Hence it is not possible to have a polygon, the sum of whose interior angles is 870°