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ICSE-VIII-Mathematics

08: Profit, Loss and Discount Class 8 Maths

with Solutions - page 4

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  • Qstn #10
    A tape-recorder is sold for Rs. 2,760 at a gain of 15% and a C.D. player is sold for Rs. 3,240 at a loss of 10% Find :
    Ans : S.P. of tape-recorder = Rs, 2,760
    Gain = 15%
  • #10-i
    the C.P. of the tape-recorder
    Ans : C.P. = (100 × S.P.)/115 [C.P. = (100 × S.P.)/(100 + Gain)]
    = (100 × 2760)/115
    = (20 × 2760)/23
    = 20 × 120
    = Rs. 2400
  • #10-ii
    the C.P. of the C.D. player.
    Ans : S.P. of C.D. player = Rs. 3,240
    [C.P. = 100/(100 - Loss) × S.P.]
    = 100/(100 - 10) × 3240
    = 100/90 × 3240
    = 100 × 36
    = Rs. 3600
  • #10-iii
    the total C.P. of both.
    Ans : Total C.P. Of both = Rs. 2400 + Rs 3600 = Rs. 6000
  • #10-iv
    the total S.P. of both
    Ans : Total S.P. of both = Rs. 2760 + Rs. 3240 = Rs. 6000
  • #10-v
    the gain % or the loss % on the whole
    Ans : Since, S.P. = C.P. there is no gain and no loss on the whole.
  • Qstn #11
    Rajesh sold his scooter to Rahim at 8% loss and Rahim, in turn, sold the same scooter to Prem at 5% gain. If Prem paid Rs. 14,490 for the scooter ; find :
    Ans : Let C.P. of the scooter for Rajesh = Rs 100x
    S.P. for Rajesh = (100x × 92)/100 = 92x
    This will be C.P. for Rahim = 92x, Gain = 5%
    ∴ S.P. for Rahim = (92x × 105)/100
    = (92x × 21)/20
    = (46x × 21)/10
    = 966x/10
    This will be C.P. for Prem = Rs. 14,490
    ∴ 966x/10 = 14,490
    ⇒ x = 14490/966 × 10
    = 14490/483 × 5
    = 30 × 5
    = 150
  • #11-i
    the S.P. and the C.P. of the scooter for Rahim
    Ans : C.P. of scooter for Rahim = 92x = 92 × 150
    = Rs. 13800
    S.P. of scooter for Rahim = 966x/10
    = 966/10 × 150
    = Rs. 966 × 15
    = Rs. 14490
  • #11-ii
    the S.P. and the C.P. of the scooter for Rajesh
    Ans : ∴ C.P. of Scooter for Rajesh = 100x = 100 × 150
    = Rs. 15000
    S.P. of Scooter for Rajesh = 92x = Rs. 92 × 150
    = Rs. 13800
  • Qstn #12
    John sold an article to Peter at 20% profit and Peter sold it to Mohan at 5% loss. If Mohan paid Rs.912 for the article; find how much did John pay for it?
    Ans : Mohan paid for the article = Rs. 912
    ∵ Peter sold the article to Mohan
    ∴ For Peter :
    S.P. = Rs. 912
    Loss = 5%
    C.P. = 100/(100 - Loss%) × S.P.
    = 100/(100 - 5) × 912
    = Rs. (100 × 912)/95
    = 20 × 48
    = Rs. 960
    John sold the same article to Peter
    ∴ For John:
    S.P. = Rs. 960
    Profit = 20%
    C.P. = 100/(100 + Profit%) × S.P.
    = 100/(100 + 20) × Rs. 960
    = Rs. 100/120 × 960
    = Rs. 100 × 8
    = Rs. 800
    Hence, John paid for the article = Rs. 800
  • #
    Section : C
  • Qstn #1
    A stationer buys pens at 5 for Rs.28 and sells them at a profit of 25 %. How much should a customer pay; if he buys
    Ans : For Stationer:
    C.P. of 5 pens = Rs. 28
    C.P. of 1 pen = Rs.28/5 = Rs. 5.60
    Profit = 25%
    ∴ S.P. of 1 pen = (100 + Profit%)/100 × C.P. of 1 Pen
    = (100 + 25)/100 × Rs. 5.60
    = Rs. 125/100 × 5.60
    = Rs. (125 × 5.6)/100
    = Rs. 5 × 1.4
    = Rs 7
    S.P. of 3 pens = 3 × 7 = Rs. 21
    ∴ Customer pays for
  • #1-i
    only one pen ;
    Ans : only one pen = Rs. 7
  • #1-ii
    three pens?
    Ans : Three pens = Rs. 21
  • Qstn #2
    A fruit-seller sells 4 oranges for Rs. 3, gaining 50%. Find :
    Ans : S.P. of 4 oranges = Rs. 3
    ∴ S.P. of 1 orange = Rs. ¾, Gain = 50%
    S.P. = (C.P. × 150)/100
    ∴ C.P. of 1 orange = (100 × S.P.)/(100 + 50)
    = (100 × ¾)/150
    = 75/150
    = Re ½
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