ICSE-VIII-Mathematics
08: Profit, Loss and Discount Class 8 Maths
- #10A tape-recorder is sold for Rs. 2,760 at a gain of 15% and a C.D. player is sold for Rs. 3,240 at a loss of 10% Find : (i) the C.P. of the tape-recorder (ii) the C.P. of the C.D. player. (iii) the total C.P. of both. (iv) the total S.P. of both (v) the gain % or the loss % on the whole (i) the C.P. of the tape-recorder (ii) the C.P. of the C.D. player. (iii) the total C.P. of both. (iv) the total S.P. of both (v) the gain % or the loss % on the whole (i) the C.P. of the tape-recorder (ii) the C.P. of the C.D. player. (iii) the total C.P. of both. (iv) the total S.P. of both (v) the gain % or the loss % on the wholeAns : S.P. of tape-recorder = Rs, 2,760
Gain = 15% (i) C.P. = (100 × S.P.)/115 [C.P. = (100 × S.P.)/(100 + Gain)]
= (100 × 2760)/115
= (20 × 2760)/23
= 20 × 120
= Rs. 2400 (ii) S.P. of C.D. player = Rs. 3,240
[C.P. = 100/(100 - Loss) × S.P.]
= 100/(100 - 10) × 3240
= 100/90 × 3240
= 100 × 36
= Rs. 3600 (iii) Total C.P. Of both = Rs. 2400 + Rs 3600 = Rs. 6000 (iv) Total S.P. of both = Rs. 2760 + Rs. 3240 = Rs. 6000 (v) Since, S.P. = C.P. there is no gain and no loss on the whole. (i) C.P. = (100 × S.P.)/115 [C.P. = (100 × S.P.)/(100 + Gain)]
= (100 × 2760)/115
= (20 × 2760)/23
= 20 × 120
= Rs. 2400 (ii) S.P. of C.D. player = Rs. 3,240
[C.P. = 100/(100 - Loss) × S.P.]
= 100/(100 - 10) × 3240
= 100/90 × 3240
= 100 × 36
= Rs. 3600 (iii) Total C.P. Of both = Rs. 2400 + Rs 3600 = Rs. 6000 (iv) Total S.P. of both = Rs. 2760 + Rs. 3240 = Rs. 6000 (v) Since, S.P. = C.P. there is no gain and no loss on the whole. (i) C.P. = (100 × S.P.)/115 [C.P. = (100 × S.P.)/(100 + Gain)]
= (100 × 2760)/115
= (20 × 2760)/23
= 20 × 120
= Rs. 2400 (ii) S.P. of C.D. player = Rs. 3,240
[C.P. = 100/(100 - Loss) × S.P.]
= 100/(100 - 10) × 3240
= 100/90 × 3240
= 100 × 36
= Rs. 3600 (iii) Total C.P. Of both = Rs. 2400 + Rs 3600 = Rs. 6000 (iv) Total S.P. of both = Rs. 2760 + Rs. 3240 = Rs. 6000 (v) Since, S.P. = C.P. there is no gain and no loss on the whole.
- #10-ithe C.P. of the tape-recorderAns : C.P. = (100 × S.P.)/115 [C.P. = (100 × S.P.)/(100 + Gain)]
= (100 × 2760)/115
= (20 × 2760)/23
= 20 × 120
= Rs. 2400
- #10-iithe C.P. of the C.D. player.Ans : S.P. of C.D. player = Rs. 3,240
[C.P. = 100/(100 - Loss) × S.P.]
= 100/(100 - 10) × 3240
= 100/90 × 3240
= 100 × 36
= Rs. 3600
- #10-iiithe total C.P. of both.Ans : Total C.P. Of both = Rs. 2400 + Rs 3600 = Rs. 6000
- #10-ivthe total S.P. of bothAns : Total S.P. of both = Rs. 2760 + Rs. 3240 = Rs. 6000
- #10-vthe gain % or the loss % on the wholeAns : Since, S.P. = C.P. there is no gain and no loss on the whole.