ICSE-VIII-Mathematics

08: Profit, Loss and Discount Class 8 Maths

with Solutions - page 4
  • #2
    A fruit-seller sells 4 oranges for Rs. 3, gaining 50%. Find : (i) C.P. of 4 oranges, (ii) C.P. of one orange. (iii) S.P. of one orange. (iv) profit made by selling one orange. (v) number of oranges brought and sold in order to gain Rs. 24. (i) C.P. of 4 oranges, (ii) C.P. of one orange. (iii) S.P. of one orange. (iv) profit made by selling one orange. (v) number of oranges brought and sold in order to gain Rs. 24.
    Ans : S.P. of 4 oranges = Rs. 3
    ∴ S.P. of 1 orange = Rs. ¾, Gain = 50%
    S.P. = (C.P. × 150)/100
    ∴ C.P. of 1 orange = (100 × S.P.)/(100 + 50)
    = (100 × ¾)/150
    = 75/150
    = Re ½ (i) C.P. of 4 oranges = 4 ×1/2 = Rs. 2 (ii) C.P. of 1 oranges = Rs. ½ = Rs. (0.50) (iii) S.P. of 1 orange = Rs. ¾ = Rs. 0.75 (iv) Profit made by selling one orange = Rs. ¾ - Rs. ½
    = Rs. ¼
    = Rs. 0.25 (v) If gain is Rs. ¼; number of oranges = 1
    If gain is Rs. 24, number of oranges = (1/1)/4 × 24
    = 1 × 4/1 × 24
    = 96 (i) C.P. of 4 oranges = 4 ×1/2 = Rs. 2 (ii) C.P. of 1 oranges = Rs. ½ = Rs. (0.50) (iii) S.P. of 1 orange = Rs. ¾ = Rs. 0.75 (iv) Profit made by selling one orange = Rs. ¾ - Rs. ½
    = Rs. ¼
    = Rs. 0.25 (v) If gain is Rs. ¼; number of oranges = 1
    If gain is Rs. 24, number of oranges = (1/1)/4 × 24
    = 1 × 4/1 × 24
    = 96
  • #2-i
    C.P. of 4 oranges,
    Ans : C.P. of 4 oranges = 4 ×1/2 = Rs. 2
  • #2-ii
    C.P. of one orange.
    Ans : C.P. of 1 oranges = Rs. ½ = Rs. (0.50)
  • #2-iii
    S.P. of one orange.
    Ans : S.P. of 1 orange = Rs. ¾ = Rs. 0.75
  • #2-iv
    profit made by selling one orange.
    Ans : Profit made by selling one orange = Rs. ¾ - Rs. ½
    = Rs. ¼
    = Rs. 0.25
  • #2-v
    number of oranges brought and sold in order to gain Rs. 24.
    Ans : If gain is Rs. ¼; number of oranges = 1
    If gain is Rs. 24, number of oranges = (1/1)/4 × 24
    = 1 × 4/1 × 24
    = 96