ICSE-VIII-Mathematics
08: Profit, Loss and Discount Class 8 Maths
- #2A fruit-seller sells 4 oranges for Rs. 3, gaining 50%. Find : (i) C.P. of 4 oranges, (ii) C.P. of one orange. (iii) S.P. of one orange. (iv) profit made by selling one orange. (v) number of oranges brought and sold in order to gain Rs. 24. (i) C.P. of 4 oranges, (ii) C.P. of one orange. (iii) S.P. of one orange. (iv) profit made by selling one orange. (v) number of oranges brought and sold in order to gain Rs. 24.Ans : S.P. of 4 oranges = Rs. 3
∴ S.P. of 1 orange = Rs. ¾, Gain = 50%
S.P. = (C.P. × 150)/100
∴ C.P. of 1 orange = (100 × S.P.)/(100 + 50)
= (100 × ¾)/150
= 75/150
= Re ½ (i) C.P. of 4 oranges = 4 ×1/2 = Rs. 2 (ii) C.P. of 1 oranges = Rs. ½ = Rs. (0.50) (iii) S.P. of 1 orange = Rs. ¾ = Rs. 0.75 (iv) Profit made by selling one orange = Rs. ¾ - Rs. ½
= Rs. ¼
= Rs. 0.25 (v) If gain is Rs. ¼; number of oranges = 1
If gain is Rs. 24, number of oranges = (1/1)/4 × 24
= 1 × 4/1 × 24
= 96 (i) C.P. of 4 oranges = 4 ×1/2 = Rs. 2 (ii) C.P. of 1 oranges = Rs. ½ = Rs. (0.50) (iii) S.P. of 1 orange = Rs. ¾ = Rs. 0.75 (iv) Profit made by selling one orange = Rs. ¾ - Rs. ½
= Rs. ¼
= Rs. 0.25 (v) If gain is Rs. ¼; number of oranges = 1
If gain is Rs. 24, number of oranges = (1/1)/4 × 24
= 1 × 4/1 × 24
= 96
- #2-iC.P. of 4 oranges,Ans : C.P. of 4 oranges = 4 ×1/2 = Rs. 2
- #2-iiC.P. of one orange.Ans : C.P. of 1 oranges = Rs. ½ = Rs. (0.50)
- #2-iiiS.P. of one orange.Ans : S.P. of 1 orange = Rs. ¾ = Rs. 0.75
- #2-ivprofit made by selling one orange.Ans : Profit made by selling one orange = Rs. ¾ - Rs. ½
= Rs. ¼
= Rs. 0.25
- #2-vnumber of oranges brought and sold in order to gain Rs. 24.Ans : If gain is Rs. ¼; number of oranges = 1
If gain is Rs. 24, number of oranges = (1/1)/4 × 24
= 1 × 4/1 × 24
= 96