CBSE-XI-Physics
02: Physics and Mathematics
- #2Let
C→=A→+B→(a)
C→is always greater than
A→(b) It is possible to have
C→<
A→and
C→<
B→(c) C is always equal to A + B
(d) C is never equal to A + B.digAnsr: bAns : (b) It is possible to have `` \left|\stackrel{\to }{C}\right|`` < `` \left|\stackrel{\to }{A}\right|`` and `` \left|\stackrel{\to }{C}\right|`` < `` \left|\stackrel{\to }{B}\right|``
Statements (a), (c) and (d) are incorrect.
Given: `` \stackrel{\to }{C}=\stackrel{\to }{A}+\stackrel{\to }{B}``
Here, the magnitude of the resultant vector may or may not be equal to or less than the magnitudes of `` \stackrel{\to }{A}`` and `` \stackrel{\to }{B}`` or the sum of the magnitudes of both the vectors if the two vectors are in opposite directions.
Page No 28: