NEET-XII-Physics

exam-2 year:2016

with Solutions -
  • #96
    An electron is moving in a circular path under the
    influence of a transverse magnetic field of
    3.57 ``10^{-2}`` T. If the value of e/m is
    1.76 X ``10^{11}`` C/kg, the frequency of revolution of
    the electron is :-
    (1) 62.8 MHz
    (2) 6.28 MHz
    (3) 1 GHz
    (4) 100 MHz
    digAnsr:   3
    Ans : (3)
    Sol. f =

    eB
    2 m
      
    =

    11 21.76 10 3.57 10
    f
    2 3.14
    Hz
    f = 109 Hz or 1 GHz