NEET-XII-Physics

exam-2 year:2016

with Solutions -
  • #94
    A long wire carrying a steady current is bent into
    a circular loop of one turn. The magnetic field at
    the centre of the loop is B. It is then bent into a
    circular coil of n turns. The magnetic field at the
    centre of this coil of n turns will be :-
    (1) 2nB
    (2) ``2n^2B``
    (3) nB
    (4) ``n^2B``
    digAnsr:   4
    Ans : (4)
    Sol. Since  = 2R = n(2r) &implies; =
    R
    r
    n
    For one turn 0iB
    2R

    = and
    For n turn 0niB '
    2r

    =
    &implies;

     = =
    2
    20n iB n B
    2R