NEET-XII-Physics
exam-2 year:2016
- #94A long wire carrying a steady current is bent into
a circular loop of one turn. The magnetic field at
the centre of the loop is B. It is then bent into a
circular coil of n turns. The magnetic field at the
centre of this coil of n turns will be :-
(1) 2nB
(2) ``2n^2B``
(3) nB
(4) ``n^2B``digAnsr: 4Ans : (4)
Sol. Since = 2R = n(2r) &implies; =
R
r
n
For one turn 0iB
2R
= and
For n turn 0niB '
2r
=
&implies;
= =
2
20n iB n B
2R