NEET-XII-Physics

exam-2 year:2016

with Solutions - page 2
 
  • Qstn #105
    A linear aperture whose width is 0.02 cm is placed
    immediately in front of a lens of focal length 60 cm.
    The aperture is illuminated normally by a parallel
    beam of wavelength 5 X ``10^{-5}`` cm. The distance of
    the first dark band of the diffraction pattern from
    the centre of the screen is :-
    (1) 0.20 cm
    (2) 0.15 cm
    (3) 0.10 cm
    (4) 0.25 cm
    digAnsr:   2
    Ans : (2)
    Sol. f = D = 60 cm
    For first minima,
    -7 -3
    -2 -2
    D 5 10 60 5 10 60
    y
    a 2 10 10 2
        
    = = =
     
    = 0.15 cm
  • Qstn #106
    Electrons of mass m with de-Broglie wavelength ``\lambda``
    fall on the target in an X-ray tube. The cutoff
    wavelength (``\lambda_0``) of the emitted X-ray is :-
    (1)``\lambda_0``= ``\frac {2m^2c^2\lambda^3}{h^2}``
    (2) ``\lambda_0``= ``\lambda``
    (3)``\lambda_0``= ``\frac {2mc\lambda^2}{h}``
    (4) ``\lambda_0``= ``\frac {2h}{mc}``
    digAnsr:   3
    Ans : (3)
    Sol.
    h h
    p
    p
    = &implies; =

    KE of electrons = = =

    2 2
    2
    p h
    E
    2m 2m
    Also in X-ray 0
    hc
    E
     = &implies;
    2
    0
    2mc
    h

     =
  • Qstn #107
    Photons with energy 5 eV are incident on a
    cathode C in a photoelectric cell. The maximum
    energy of emitted photoelectrons is 2 eV. When
    photons of energy 6 eV are incident on C, no
    photoelectrons will reach the anode A, if the
    stopping potential of A relative to C is :-
    (1) - 1 V
    (2) - 3 V
    (3) + 3 V
    (4) + 4 V
    digAnsr:   2
    Ans : (2)
    Sol. = =   2s max 0
    1
    eV mv h
    2
    2 = 5 - &implies;=3 eV
    In second case
    eVs = 6 - 3 = 3 eV &implies;Vs = 3 V.
    ∴ VAC = -3 V
  • Qstn #108
    If an electron in a hydrogen atom jumps from the
    3rd orbit to the 2nd orbit, it emits a photon of
    wavelength ``\lambda``. When it jumps from the 4th orbit to
    the 3rd orbit, the corresponding wavelength of the
    photon will be :-
    (1)20/7 ``\lambda``
    (2)20/13 ``\lambda``
    (3)16/25 ``\lambda``
    (4)9/16 ``\lambda``
    digAnsr:   1
    Ans : (1)
    Sol. Transition : 3 2 &implies;Wavelength 
    Transition : 4 3 &implies;Wavelength '=
    2
    2 2
    2
    2 2
    1 1 1
    RZ
    ' 20 202 3 '
    1 1 1 7 7
    RZ
    ' 3 4
     
    =      &implies; = &implies;  =
     
    =    
  • Qstn #109
    The half-life of a radioactive substance is 30 minutes.
    The time (in minutes) taken between 40% decay and
    85% decay of the same radioactive substance is :-
    (1) 45
    (2) 60
    (3) 15
    (4) 30
    digAnsr:   2
    Ans : (2)
    Sol. decay 40% 85%
    Remaining 60% 15%
    60%
    1
    2
    t
     30%
    1
    2
    t
     15%
    ∴t = 2t1/2 = 60 min.
  • Qstn #110
    For CE transistor amplifier, the audio signal voltage
    across the collector resistance of 2 k``\Omega`` is 4 V. If the
    current amplification factor of the transistor is
    100 and the base resistance is 1 k``\Omega``, then the input
    signal voltage is :-
    (1) 30 mV
    (2) 15 mV
    (3) 10 mV
    (4) 20 mV
    digAnsr:   4
    Ans : (4)
    Sol. = 100; V0 = 4V; Ri = 103 ;
    R0 = 2 × 103 ; Vi = ?
    AV =
    3
    0 0
    3
    i i i
    V R 4 2 10
    100
    V R V 10

    =  &implies; = 
    &implies; Vi = 20 mV
  • Qstn #111
    The given circuit has two ideal diodes connected as
    shown in the figure below. The current flowing
    through the resistance ``R_``1 will be :-

    (1) 1.43 A
    (2) 3.13 A
    (3) 2.5 A
    (4) 10.0 A
    digAnsr:   3
    Ans : (3)
    Sol. Current will not flow through D1 as it is reverse
    biased. Current will flow through cell, R1, D2 and R3.

    10
    i
    2 2
    =
    +
    = 2.5 A
    
    
    12
  • Qstn #112
    What is the output Y in the following circuit, when
    all the three inputs A,B,C are first 0 and then 1 ?

    (1) 1,0
    (2) 1,1
    (3) 0,1
    (4) 0.0
    digAnsr:   1
    Ans : (1)
    Sol.
    AB
    y = (AB)C
    P
    Q
    A
    B
    C
    for A = B = C = 0 ; y = 1
    for A = B = C = 1 ; y = 0
  • Qstn #113
    Planck's constant (h), speed of light in vacuum
    and Newton's gravitational constant (G) are three
    fundamental constants. Which of the following
    combinations of these has the dimension of length?
    (1)``\sqrt \frac {hc}{(G)}``
    (2) ``\sqrt \frac {Gc}{(h^\frac 32)}``
    (3) ``\sqrt \frac {Gh}{(c^\frac 32)}``
    (4)``\sqrt \frac {Gh}{(c^\frac 52)}``
    digAnsr:   3
    Ans : (3)
    Sol. x y zh G c
    M0L1T0 = (ML2T-1)x (M-1L3T-2)y (LT-1)z
    = Mx-y L2x+3y+z T-x-2y-z
    Equating :
    3/ 2
    1 1 3
    x y 0 x ;y ;z
    2 2 2
    2x 3y z 1
    hG
    x 2y z 0
    c
     = &implies; = = = 

    + + = 
     &implies;    =  
  • Qstn #114
    Two cars P and Q start from a point at the same
    time in a straight line and their positions are
    represented by ``x_p(t) = at + bt^2`` and ``x_Q (t) = ft - t^2``.
    At what time do the cars have the same velocity ?
    (1)``\frac {a+ f}{2(1+ b)}``
    (2)``\frac { f -a}{2(1+ b)}``
    (3)``\frac {a- f}{(1+ b)}``
    (4)``\frac {a+ f}{2(b - 1)}``
    digAnsr:   2
    Ans : (2)
    Sol. xP(t) = at + bt2 xQ(t) = ft - t2
    vP = a + 2bt vQ = f - 2t
    as vP = vQ
    a + 2bt = f - 2t
    &implies;
    f a
    t
    2(1 b)

    =
    +
  • Qstn #115
    In the given figure, a = 15 ``\frac {m}{s^2}`` represents the total
    acceleration of a particle moving in the clockwise
    direction in a circle of radius R = 2.5 m at a given
    instant of time. The speed of the particle is :-

    (1) 5.7 m/s
    (2) 6.2 m/s
    (3) 4.5 m/s
    (4) 5.0 m/s
    digAnsr:   1
    Ans : (1)
    Sol. Centripetal acceleration =
    2v
    a cos30
    R
    = 
    &implies;
    3
    v aRcos30 15 2.5
    2
    =  =   = 5.7m/s
  • Qstn #116
    A rigid ball of mass m strikes a rigid wall at 60° and
    gets reflected without loss of speed as shown in the
    figure below. The value of impulse imparted by the
    wall on the ball will be :-

    (1)mV/2
    (2)mV/3
    (3) mV
    (4) 2mV
    digAnsr:   3
    Ans : (3)
    Sol. Impulse p m V m(2V cos60 )= ▵ = ▵ = 
     
    = mV
    
    
    13
  • Qstn #117
    A bullet of mass 10g moving horizontally with a
    velocity of 400 ``ms^{-1}`` strikes a wooden block of mass
    2 kg which is suspended by a light inextensible string
    of length 5 m. As a result, the centre of gravity of
    the block is found to rise a vertical distance of
    10 cm. The speed of the bullet after it emerges out
    horizontally from the block will be :-
    (1) 120 ``ms^{-1}``
    (2) 160 ``ms^{-1}``
    (3) 100 ``ms^{-1}``
    (4) 80 ``ms^{-1}``
    digAnsr:   1
    Ans : (1)
    Sol.
    2kg
    2kg v1
    v210gm
    400 m/s
    0.1 m
    5m
    Applying momentum conservation
    1 2
    10 10
    400 0 2 v v
    1000 1000
     + =  + 
    &implies; 4 = 2v1 + 0.01v2 ......(1)
    Applying work energy theorem for block
    W = ▵KE
    &implies; 2 × 10 × 0.1 =
    1
    2
    × 2 × v12
    &implies; v1 = 2 = 1.4 m/s
    Putting the value of v1 in equation (1)
    4 = 2 × 1.4 + 0.01 v2 &implies;v2 = 120 m/s
  • Qstn #118
    Two identical balls A and B having velocities of
    0.5 m/s and -0.3 m/s respectively collide elastically
    in one dimension. The velocities of B and A after
    the collision respectively will be :-
    (1) -0.3 m/s and 0.5 m/s
    (2) 0.3 m/s and 0.5 m/s
    (3) -0.5 m/s and 0.3 m/s
    (4) 0.5 m/s and -0.3 m/s
    digAnsr:   4
    Ans : (4)
    Sol. Since both bodies are identical and collision is elastic.
    Therefore velocities will be interchanged after
    collision.
    vA = -0.3 m/s and vB = 0.5 m/s
  • Qstn #119
    A particle moves from a point ``(-2\hat{i} + 5\hat{j})`` to
    + ``(4\hat{j} + 3\hat{k})`` when a force of ``(4\hat{i} + 3\hat{j})`` N is applied.
    How much work has been done by the force ?
    (1) 5 J
    (2) 2 J
    (3) 8 J
    (4) 11 J
    digAnsr:   1
    Ans : (1)
    Sol. f i ˆˆ ˆs r r 2i j 3k=  =  +
      
      ˆˆ ˆ ˆW F.s 4i 3j . 2i j 3k 8 3 5J = = +  + =  = 
     