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NEET-XII-Physics
exam-2 year:2016
- #107Photons with energy 5 eV are incident on a
cathode C in a photoelectric cell. The maximum
energy of emitted photoelectrons is 2 eV. When
photons of energy 6 eV are incident on C, no
photoelectrons will reach the anode A, if the
stopping potential of A relative to C is :-
(1) - 1 V
(2) - 3 V
(3) + 3 V
(4) + 4 VdigAnsr: 2Ans : (2)
Sol. = = 2s max 0
1
eV mv h
2
2 = 5 - &implies;=3 eV
In second case
eVs = 6 - 3 = 3 eV &implies;Vs = 3 V.
∴ VAC = -3 V