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NEET-XII-Physics

exam-2 year:2016

with Solutions - page 2
  • #107
    Photons with energy 5 eV are incident on a
    cathode C in a photoelectric cell. The maximum
    energy of emitted photoelectrons is 2 eV. When
    photons of energy 6 eV are incident on C, no
    photoelectrons will reach the anode A, if the
    stopping potential of A relative to C is :-
    (1) - 1 V
    (2) - 3 V
    (3) + 3 V
    (4) + 4 V
    digAnsr:   2
    Ans : (2)
    Sol. = =   2s max 0
    1
    eV mv h
    2
    2 = 5 - &implies;=3 eV
    In second case
    eVs = 6 - 3 = 3 eV &implies;Vs = 3 V.
    ∴ VAC = -3 V