NEET-XII-Physics

pp year:2018

with Solutions -
 
  • Qstn #1
    An em wave is propagating in a medium with a
    velocity``\vec{V}``= V``\hat{i}``.
    The instantaneous oscillating electric field
    of this em wave is along +y axis. Then the
    direction of oscillating magnetic
    field of the em wave will be along :-
    (1) -z direction
    (2) +z direction
    (3) -y direction
    (4) -x direction
    digAnsr:   2
    Ans : (2)
    Sol. = ˆ ˆ ˆV E B , =  ˆˆ ˆi j k
    ∴ = ˆB̂ k , +z direction
  • Qstn #2
    The refractive index of the material of a prism
    is ``\sqrt2`` and the angle of the prism is 30°. One of the
    two refracting surfaces of the prism is made a mirror
    inwards, by silver coating. A beam of
    monochromatic light entering the prism from the
    other face will retrace its path (after reflection from
    the silvered surface) if its angle of incidence on the
    prism is :-
    (1) 60°
    (2) 45°
    (3) 30°
    (4) zero
    digAnsr:   2
    Ans : (2)
    Sol.
    30°
    r =30°1
    µ = 2
    i
    r =0°2
    r2 = 0, r1 = A = 30°
    sin i = 2 sin30 =  =
    1 1
    2
    2 2
    i = 45°
  • Qstn #3
    The magnetic potential energy stored in a
    certain inductor is 25 mJ, when the current
    in the inductor is 60 mA. This inductor is
    of inductance :-
    (1) 0.138 H
    (2) 138.88 H
    (3) 1.389 H
    (4) 13.89 H
    digAnsr:   4
    Ans : (4)
    Sol. = 2
    1
    PE LI
    2
      = 3 3 2
    1
    25 10 L(60 10 )
    2
    L = 13.89 H
  • Qstn #4
    An object is placed at a distance of 40 cm
    from a concave mirror of focal length 15 cm.
    If the object is displaced through a distance
    of 20 cm towards the mirror, the displacement
    of the image will be:-
    (1) 30 cm away from the mirror
    (2) 36 cm away from the mirror
    (3) 30 cm towards the mirror
    (4) 36 cm towards the mirror
    digAnsr:   2
    Ans : (2)
    Sol. (i)
    object
    40 cm
    f = 15 cm
    0
     
    = =
      +
    1
    uf ( 40)( 15)
    v
    u f 40 15
    = = 

    600
    24cm
    25
    (ii)
    /////////////////////////////
    object
    20 cm
    f = 15 cm
     
    = =
      +
    2
    uf ( 20) ( 15)
    v
    u f 20 15
    = -60 cm
    Displacement of image = v2 - v1 = -36 cm
    = 36 cm away from the mirror.
  • Qstn #5
    In the combination of the following gates the
    output Y can be written in terms of inputs A
    and B as :-
    p5.png
    (1)`` \bar {A.B} ``
    (2) A . ``\bar B`` + ``\bar A . B``
    (3) `` \bar {A.B} ``+ A.B
    (4) ``\bar {A+B}``
    digAnsr:   2
    Ans : (2)
    Sol. A
    B
    A
    B
    A
    B
    A.B
    A.B
    A.B + A.B
    PHYSICS
    
    
    2
    NEET(UG)-2018
  • Qstn #6
    In the circuit shown in the figure, the input
    voltage``V_i`` is 20 V, ``V_{BE}`` = 0 and
    ``V_{CE}`` = 0. The values of ``I_B``, ``I_C``
    and ``\beta`` are given by :-
    p6.png
    (1) ``I_B``= 40 ``\mu A``, ``I_C``= 10 mA, ``\beta``= 250
    (2) ``I_B``= 25 ``\mu A``, ``I_C``= 5 mA, ``\beta``= 200
    (3) ``I_B``= 20 ``\mu A``, ``I_C``= 5 mA, ``\beta``= 250
    (4) ``I_B``= 40 ``\mu A``, ``I_C``= 5 mA, ``\beta``= 125
    digAnsr:   4
    Ans : (4)
    Sol. Vi = IBRB + VBE
    20 = IB × (500 × 10
    3) + 0
    = =

    B 3
    20
    I 40µA
    500 10
    = +CC C C CEV I R V
    20 = IC × (4 × 10
    3) + 0
    IC = 5 × 10
    -3 = 5 mA



     = = =

    3
    C
    6
    B
    I 5 10
    125
    I 40 10
  • Qstn #7
    In a p-n junction diode, change in temperature
    due to heating :-
    (1) affects only reverse resistance
    (2) affects only forward resistance
    (3) does not affect resistance of p-n junction
    (4) affects the overall V - I characteristics
    of p-n junction
    digAnsr:   4
    Ans : (4)
    Sol. Affects the overall V - I characteristics of p-n
    junction
  • Qstn #8
    A small sphere of radius 'r' falls from rest in a
    viscous liquid. As a result, heat is produced due to
    viscous force. The rate of production of heat when
    the sphere attains its terminal velocity, is
    proportional to :-
    (1) ``r^3``
    (2) ``r^2``
    (3) ``r^5``
    (4) ``r^4``
    digAnsr:   3
    Ans : (3)
    Sol. Rate of heat produced
    = v T
    dQ
    F V
    dt
     =   

    2
    T
    2r
    V ( )g
    9
    = 6rVT × VT ∴ VT  r
    2
     2T
    dQ
    rV
    dt
     VT  r
    2
     5
    dQ
    r
    dt
  • Qstn #9
    A sample of 0.1 g of water at 100°C and
    normal pressure (1.013 x ``10^5`` ``Nm^{-2}``)
    requires 54 cal of heat energy to convert
    to steam at ``100^o``C. If the volume of the
    steam produced is 167.1 cc, the change in
    internal energy of the sample, is :-
    (1) 104.3 J
    (2) 208.7 J
    (3) 42.2 J
    (4) 84.5 J
    digAnsr:   2
    Ans : (2)
    Sol. ▵Q = 54 cal = 54 × 4.18 joule = 225.72 joule
    ▵W = P[Vsteam - Vwater] [For water 0.1 gram=0.1 cc]
    = 1.013 × 105[167.1 × 10-6 - 0.1 × 10-6] joule
    = 1.013 × 167 × 10-1 = 16.917 joule
    By FLOT
    &implies; ▵U = ▵Q - ▵W = 225.72 - 16.917
    ▵U = 208.8 joule
  • Qstn #10
    Two wires are made of the same material
    and have the same volume. The first wire
    has cross-sectional area A and the second
    wire has cross-sectional area 3A. If the
    length of the first wire is increased by
    ``\triangle l`` on applying a force F,
    how much force is needed to stretch the
    second wire by the same amount ?
    (1) 9F
    (2) 6F
    (3) 4F
    (4) F
    digAnsr:   1
    Ans : (1)
    Sol. =



    F
    Y
    A
     V = A so =
    V
    A
    ▵ ▵
    = =
     

    2YA YA
    F
    V
     
    =  
     
    2
    1 1
    2 2
    F A
    F A &implies;
     
    = = 
     
    2
    2
    F A 1
    F 3A 9
    F2 = 9F
  • Qstn #11
    The power radiated by a black body is P and
    it radiates maximum energy at wavelength ``\lambda _0``.
    If the temperature of the black body is now
    changed so that it radiates maximum energy at
    wavelength ``\frac{3}{4}````\lambda _0``
    , the power radiated by it becomes nP. The
    value of n is :-
    (1)``\frac{3}{4}``
    (2)``\frac{4}{3}``
    (3)``\frac{256}{81}``
    (4)``\frac{81}{256}``
    digAnsr:   3
    Ans : (3)
    Sol. P = AT4 &implies; P  T4
    According to Wein's law 
    m
    1
    T
    &implies;
     
       
    4
    m
    1
    P &implies;
     
    =    
    1
    2
    4
    m2
    1 m
    P
    P
    &implies;
     
    =  
     
     
    4
    2 0
    1
    0
    P
    3P
    4
    &implies; = &implies; =
    nP 256 256
    n
    P 81 81
    
    
    3
    CODE - PP
  • Qstn #12
    A set of 'n' equal resistors, of value 'R' each,
    are connected in series to a battery of emf 'E'
    and internal resistance 'R'. The current drawn is I.
    Now, the 'n' resistors are connected in parallel
    to the same battery. Then the current drawn from
    battery becomes 10 I. The value of 'n' is :-
    (1) 10
    (2) 11
    (3) 20
    (4) 9
    digAnsr:   1
    Ans : (1)
    Sol. =
    +
    E
    I
    nR R
    ..... (1)
    = =
    +
    +
    E nE
    10I
    R R nRR
    n
    .....(2)
    From (1) & (2),
     
    =  
    +  + 
    E E
    n 10
    R nR nR R
    n = 10
  • Qstn #13
    A battery consists of a variable number 'n' of
    identical cells (having internal resistance 'r' each)
    which are connected in series. The terminals of
    the battery are short-circuited and the current I
    is measured. Which of the graphs shows the
    correct relationship between I and n ?
    (1)p13a.png
    (2)p13b.png
    (3)p13c.png
    (4)p13d.png
    digAnsr:   1
    Ans : (1)
    Sol. = = =
    nE E
    I constant
    nr r
  • Qstn #14
    A carbon resistor (47 ``\pm``4.7) ``k\Omega `` is to be
    marked with rings of different colours for its
    identification. The colour code sequence will be :-
    (1) Violet - Yellow - Orange - Silver
    (2) Yellow - Violet - Orange - Silver
    (3) Yellow - Green - Violet - Gold
    (4) Green - Orange - Violet - Gold
    digAnsr:   2
    Ans : (2)
    Sol. =   3R (47 4.7) 10
    =   3R 47 10 10%
    As per color code, 3 - Orange, 4 - Yellow, 7 - Violet,
    10% - Silver