NEET-XII-Chemistry

Previous Year Paper year:2018

with Solutions -
  • #51
    In the reaction
    n51.png
    the electrophile involved is
    (1) dichloromethyl cation ``\ce{(CHCl2)^\oplus}``
    (2) formyl cation ``\ce{(CHO)^\oplus}``
    (3) dichloromethyl anion ``\ce{(CHCl2)^\ominus}``
    (4)dichlorocarbene ``\ce{(:CCl2)}``
    digAnsr:   4
    Ans : (4)
    Sol.
    OH
    CHCl3
    NaOH
    O Na
    CHCl + NaOH 3  CCl + H O3 2
    -Cl ( -Elimination)
    :CCl dichlorocarbene
    (electrophile)
    2

    CHO