NEET-XII-Physics
14: Some Mechanical Properties of Matter
- #27Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to 1 mm. Find the rise of water in the space between the plates. Surface tension of water = 0.075 Nm-1.Ans : Given:
Surface tension of water T = 0.075 N/m
Separation between the glass plates d = 1 mm = 10-3 m
Density of water ρ = 103 kg/m3
Applying law of conservation of energy:
T (2L) = [1 × (10-3) × h] ρg
`` \Rightarrow h=\frac{2\times \left(0.075\right)}{{10}^{-3}\times {10}^{3}\times 10}``
`` =0.015\,\mathrm{\,m\,}=1.5\,\mathrm{\,cm\,}``
Therefore, the rise of water in the space between the plates is 1.5 cm.
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