NEET-XII-Physics
12: Simple Harmonic Motion
- #8The displacement of a particle is given by
r→=Ai→ cosωt + j→sinωt.The motion of the particle is
(a) simple harmonic
(b) on a straight line
(c) on a circle
(d) with constant accelerationdigAnsr: cAns : (c) on a circle
We know, `` \frac{{d}^{2}}{d{t}^{2}}\stackrel{\to }{r}=-{\omega }^{2}\stackrel{\to }{r}``
`` ``
But there is a phase difference of 90o between the x and y components because of which the particle executes a circular motion and hence, the projection of the particle on the diameter executes a simple harmonic motion.
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