NEET-XII-Physics
11: Gravitation
- #1Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitational force of attraction between them.Ans : The gravitational force of attraction between the balls is given as by
`` F\mathit{=}\frac{G{m}_{\mathit{1}}{m}_{\mathit{2}}}{{r}^{\mathit{2}}}``
`` \,\mathrm{\,Given\,}:{m}_{1}={m}_{2}=10\,\mathrm{\,kg\,}\,\mathrm{\,and\,}r=10\,\mathrm{\,cm\,}=0.10\,\mathrm{\,m\,}``
`` \therefore F=\frac{6.67\times {10}^{-11}\times 10\times 10}{{\left(0.1\right)}^{2}}``
`` \Rightarrow F=6.67\times {10}^{-7}\,\mathrm{\,N\,}``
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