NEET-XII-Physics

10: Rotational Mechanics

with Solutions - page 3
Qstn# ii-21 Prvs-QstnNext-Qstn
  • #21
    A wheel of radius 20 cm is pushed to move it on a rough horizontal surface. If is found to move through a distance of 60 cm on the road during the time it completes one revolution about the centre. Assume that the linear and the angular accelerations are uniform. The frictional force acting on the wheel by the surface is
    (a) along the velocity of the wheel
    (b) opposite to the velocity of the wheel
    (c) perpendicular to the velocity of the wheel
    (d) zero.
    digAnsr:   a
    Ans : (a) along the velocity of the wheel
    As the distance covered in one revolution about the centre is less than the perimeter of the wheel, it means that the direction of torque due to frictional force opposes the motion of wheel, i.e., the frictional force acting on the wheel by the surface is along the velocity of the wheel.
    FIG.
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