NEET-XII-Physics
46: The Nucleus
- #1032P beta-decays to 32S. Find the sum of the energy of the antineutrino and the kinetic energy of the β-particle. Neglect the recoil of the daughter nucleus. Atomic mass of 32P = 31.974 u and that of 32S = 31.972 u.Ans : Given:
Atomic mass of 32P, m(32P) = 31.974 u
Atomic mass of 32S, m(32S) = 31.972 u
Reaction:
`` {\,\mathrm{\,P\,}}^{32}\to {\,\mathrm{\,S\,}}^{32}{+}_{1}{\,\mathrm{\,v\,}}^{0}{+}_{-1}{\,\mathrm{\,\beta \,}}^{0}``
Energy of antineutrino and β-particle, E = [m(32P)`` -``m(32S)]c2
= (31.974 u- 31.972 u)c2
= 0.002 × 931 = 1.862 MeV
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