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NEET-XII-Physics

43: Bohr's Model and Physics of the Atom

with Solutions - page 4
Qstn# iv-8-a Prvs-QstnNext-Qstn
  • #8-a
    Find the first excitation potential of He+ ion. (b) Find the ionization potential of Li++ ion. (b) Find the ionization potential of Li++ ion.
    Ans : PE of hydrogen like atom in the nth state, V = `` =\frac{-13.6{Z}^{2}}{{n}^{2}}\,\mathrm{\,eV\,}``
    `` ``
    Here, Z is the atomic number of that atom.
    For the first excitation, the atom has to be excited from n = 1 to n = 2 state.
    So, its excitation potential will be equal to the difference in the potential of the atom in n = 1 and in n = 2 states.
    First excitation potential of He+
    `` -13.6{Z}^{2}(1-\frac{1}{{2}^{2}})eV``
    `` =-10.2{Z}^{2}eV``
    ⇒10.2 × Z2
    = 10.2 × 4
    = 40.8 V (b) Ionization Potential Li++ = 13.6 V × Z2
    = 13.6 × 9
    = 122.4 V
    Page No 384: (b) Ionization Potential Li++ = 13.6 V × Z2
    = 13.6 × 9
    = 122.4 V
    Page No 384:
  • #8-b
    Find the ionization potential of Li++ ion.
    Ans : Ionization Potential Li++ = 13.6 V × Z2
    = 13.6 × 9
    = 122.4 V
    Page No 384: