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NEET-XII-Physics

38: Electromagnetic Induction

with Solutions - page 6
Qstn# iv-16-a Prvs-QstnNext-Qstn
  • #16-a
    t = 2 s, (b) t = 10 s, (c) t = 22 s and (d) t = 30 s.
    Figure
    Ans : At t = 2 s:
    Distance moved by the coil = 2 × 1 cm/s = 2 cm = 2 × 10`` -``2 m
    Area under the magnetic field at t = 2s, A = 2 × 5 × 10`` -``4 m2
    Initial magnetic flux = 0
    Final magnetic flux = BA = 0.6 × (10 × 10`` -``4) T-m2
    Change in the magnetic flux, Δϕ = 0.6 × (10 × 10`` -``4) `` -`` 0
    Now, induced emf in the coil is
    `` e=\frac{∆\,\mathrm{\,\varphi \,}}{∆t}``
    `` =\frac{0.6\times (10-0)\times {10}^{-4}}{2}``
    `` =3\times {10}^{-4}\,\mathrm{\,V\,}`` (b) At t = 10 s:
    Distance moved by the coil = 10 × 1 = 10 cm
    At this time square loop is completely inside the magnetic field, so there is no change in the flux linked with the coil with time.
    Therefore, induced emf in the coil at this time is zero. (c) At t = 22 s:
    Distance moved = 22 × 1 = 22 cm
    At this time loop is moving out of the field.
    Initial magnetic flux = 0.6 × (5 × 5 × 10`` -``4) T-m
    At this time 2 cm part of the loop is ou t of the field.
    Therefore, final magnetic flux = 0.6 × (3 × 5 × 10`` -``4) T-m
    Change in the magnetic flux, Δϕ = 0.6 × (3 × 5 × 10`` -``4) `` -`` 0.6 × (5 × 5 × 10`` -``4) = `` -``6 × 10`` -``4 T-m2
    Now, induced emf is
    `` e=\frac{∆\,\mathrm{\,\varphi \,}}{∆t}``
    `` =\frac{-6\times {10}^{-4}}{2}``
    `` =-3\times {10}^{-4}\,\mathrm{\,V\,}`` (d) At t = 30 s:
    At this time loop is completely out of the field, so there is no change in the flux linked with the coil with time.
    Therefore, induced emf in the coil at this time is zero.
    Page No 307:
  • #16-b
    t = 10 s,
    Ans : At t = 10 s:
    Distance moved by the coil = 10 × 1 = 10 cm
    At this time square loop is completely inside the magnetic field, so there is no change in the flux linked with the coil with time.
    Therefore, induced emf in the coil at this time is zero.
  • #16-c
    t = 22 s and
    Ans : At t = 22 s:
    Distance moved = 22 × 1 = 22 cm
    At this time loop is moving out of the field.
    Initial magnetic flux = 0.6 × (5 × 5 × 10`` -``4) T-m
    At this time 2 cm part of the loop is ou t of the field.
    Therefore, final magnetic flux = 0.6 × (3 × 5 × 10`` -``4) T-m
    Change in the magnetic flux, Δϕ = 0.6 × (3 × 5 × 10`` -``4) `` -`` 0.6 × (5 × 5 × 10`` -``4) = `` -``6 × 10`` -``4 T-m2
    Now, induced emf is
    `` e=\frac{∆\,\mathrm{\,\varphi \,}}{∆t}``
    `` =\frac{-6\times {10}^{-4}}{2}``
    `` =-3\times {10}^{-4}\,\mathrm{\,V\,}``
  • #16-d
    t = 30 s.
    Figure
    Ans : At t = 30 s:
    At this time loop is completely out of the field, so there is no change in the flux linked with the coil with time.
    Therefore, induced emf in the coil at this time is zero.
    Page No 307: