Qstnid -Iv-15-the Needle Of A Dip Circle Shows An Apparent Dip Of 45° In A Particular Position And 53° When The Circle Is Rotated Through 90°. Find The True Dip. - 36: Permanent Magnets - Neet-xii-physics

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NEET-XII-Physics

36: Permanent Magnets

with Solutions - page 4

Qstn# iv-15 Prvs-Qstn Next-Qstn

#15
The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.
Ans : Given:
Apparent dip shown by the needle of the dip circle, δ₁ = 45°
Dip shown by the needle of the dip circle on rotating the circle, δ₂= 53°
True dip `` \left(\delta \right)`` is given by
Cot² δ = Cot² δ₁ + Cot² δ₂
`` \Rightarrow ``Cot²δ = Cot² 45° + Cot² 53°
`` \Rightarrow ``Cot²δ = 1.56
`` \Rightarrow ``Cot²δ = 1.56
`` \Rightarrow ``δ = 38.6° ≈ 39°
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