NEET-XII-Physics
24: Kinetic Theory of Gases
- #29A vessel contains 1.60 g of oxygen and 2.80 g of nitrogen. The temperature is maintained at 300 K and the volume of the vessel is 0.166 m3. Find the pressure of the mixture.Ans : `` \begin{array}{l}\text{Here,}\\ \text{V = 0}{\text{.166 m}}^{3}\\ T=300K\\ {\text{Mass of O}}_{2}=1.60g\\ {M}_{O}=32g\\ {n}_{O}=\frac{1.60}{32}=0.05\\ {\text{Mass of N}}_{2}=2.80g\\ {M}_{N}=28g\\ {n}_{N}=\frac{2.80}{28}=0.1\\ {\text{Partial pressure of O}}_{2}\text{is given by}\\ {P}_{O}=\frac{{n}_{O}RT}{V}=\frac{0.05\times 8.3\times 300}{0.166}=750\\ {\text{Partial pressure of N}}_{2}\text{is given by}\\ {P}_{N}=\frac{{n}_{N}RT}{V}=\frac{0.1\times 8.3\times 300}{0.166}=1500\\ \text{Total pressure is sum of the partial pressures.}\\ \Rightarrow P={P}_{N}+{P}_{O}=750+1500=2250Pa\end{array}``
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