NEET-XII-Physics
qstns with ansrs year:2022
- #26A light ray falls on a glass surface of refractive index `` \sqrt{3} `` , at an angle `` 60^{\circ} `` . The angle between the refracted and reflected rays would be:
(A) `` 120^{\circ} ``
(B) `` 30^{\circ} ``
(C) `` 60^{\circ} ``
(D) `` 90^{\circ} ``digAnsr: DAns :
Method (i)
By Snell's law
`` 1 \sin 60^{\circ}=\sqrt{3} \sin r ``
`` \frac{\sqrt{3}}{2}=\sqrt{3} \sin r ``
`` \sin r=\frac{1}{2} ``
`` r=30^{\circ} ``
Angle between refracted and reflected ray is `` 90^{\circ} ``
Method (ii)
Because angle of incidence is Brewster's angle so that angle between reflected and refracted ray is `` 90^{\circ} ``
`` \tan i_{p}=\mu=\sqrt{3} ``
`` i_{p}=60^{\circ}= i ``