Qstnid -25-an Electric Lift With A Maximum Load Of `` 2000\, Kg `` (Lift+ Passengers) Is Moving Up With A Constant Speed Of `` 1.5 \,Ms ^{-1} `` . The Frictional Force Opposing The Motion Is `` 3000\, N `` . The Minimum Power Delivered By The Motor To The Lift In Watts Is : `` \Left(g=10 \,Ms ^{-2}\right) `` - Qstns With Ansrs Year:2022 - Neet-xii-physics

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qstns with ansrs year:2022

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Qstn# 25 Prvs-Qstn Next-Qstn

#25
An electric lift with a maximum load of `` 2000\, kg `` (lift+ passengers) is moving up with a constant speed of `` 1.5 \,ms ^{-1} `` . The frictional force opposing the motion is `` 3000\, N `` . The minimum power delivered by the motor to the lift in watts is : `` \left(g=10 \,ms ^{-2}\right) ``
(A)23500
(B)23000
(C)20000

(D)34500
digAnsr: D
Ans : Constant velocity `` \Rightarrow a =0 ``
`` \Rightarrow T = W + f ``
`` =20000+3000 ``
`` =23000 \,N ``

`` \Rightarrow `` Power `` = Tv ``
`` =23000 \times 1.5 ``
`` =34500 `` watts