NEET-XII-Physics
neet 2020 questions with solutions year:2020
- #42A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is : (g = `` 10m/s^2 `` )
(A)360 m
(B)340 m
(C)320 m
(D)300 m
digAnsr: DAns : Using, `` v^{2}=u^{2}+2gh ``
Given, `` V=80m/s `` and `` u=20 m/s ``
`` h=\frac{v^{2}-u^{2}}{2g} ``
`` =\frac{6400-400}{20} ``
`` =300\,m ``
