NEET-XII-Physics
neet 2020 questions with solutions year:2020
- #40An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is `` 1.227 \times 10^{-2}nm `` , the potential difference is :
(A) `` 10 `` V
(B) `` 10^2 `` V
(C) `` 10^3 `` V
(D) `` 10^4 `` V
digAnsr: DAns : `` \lambda = 1.227 \times 10^{-2}\,m ``
`` =0.1227 \, Å ``
`` \lambda=\frac{12.27}{\sqrt{V}} Å ``
`` 0.1227 = \frac{12.27}{\sqrt{V}} Å ``
`` \sqrt{V}\times10^{2} ``
`` \Rightarrow V=10^{4} ``