A capacitor of capacitance `` 'C' `` , is connected across an ac source of voltage `` V `` , given by `` V = V _{0} \sin \omega t ``
The displacement current between the plates of the capacitor, would then be given by:
(A) `` I _{ d }= V _{0} \omega C \cos \omega t ``
(B) `` I_{d}=\frac{V_{0}}{\omega C} \cos \omega t ``
(C) `` I _{ d }=\frac{ V _{0}}{\omega C } \sin \omega t ``
(D) `` I _{ d }= V _{0} \omega C \sin \omega t ``