NEET-XII-Physics
exam-1 year:2016
- #15A black body is at a temperature of 5760 K. The
energy of radiation emitted by the body at
wavelength 250 nm is ``U_1``, at wavelength 500 nm
is ``U_2`` and that at 1000 nm is ``U_3``. Wien's constant,
b = 2.88 × ``10^6`` nmK. Which of the following is
correct?
(1) ``U_1`` = 0
(2) ``U_3`` = 0
(3) ``U_1`` > ``U_2``
(4) ``U_2`` > ``U_1``digAnsr: 4Ans : 4
Sol. Maximum amount of emitted radiation
corresponding to m =
b
T
m =
62.88 10 nmK
5760K
= 500 nm
U
U2
Emitted
(radiation)
250nm
500nm 1000nm
From the graph U1 < U2 > U3