NEET-XII-Physics

exam-1 year:2016

with Solutions -
  • #15
    A black body is at a temperature of 5760 K. The
    energy of radiation emitted by the body at
    wavelength 250 nm is ``U_1``, at wavelength 500 nm
    is ``U_2`` and that at 1000 nm is ``U_3``. Wien's constant,
    b = 2.88 × ``10^6`` nmK. Which of the following is
    correct?
    (1) ``U_1`` = 0
    (2) ``U_3`` = 0
    (3) ``U_1`` > ``U_2``
    (4) ``U_2`` > ``U_1``
    digAnsr:   4
    Ans : 4
    Sol. Maximum amount of emitted radiation
    corresponding to m =
    b
    T
    m =
    62.88 10 nmK
    5760K

    = 500 nm
    U
    U2
    Emitted
    (radiation)
    250nm
    
    500nm 1000nm
    From the graph U1 < U2 > U3