NEET-XII-Physics
exam-1 year:2016
- #14The charge flowing through a resistance R varies
with time t as Q = at - ``bt^2``, where a and b are positive
constants. The total heat produced in R is:
(1)``\frac {a^3R}{6b}``
(2)``\frac {a^3R}{3b}``
(3) ``\frac {a^3R}{2b}``
(4)``\frac {a^3R}{b}``digAnsr: 1Ans : 1
Sol. = ï€ 2Q at bt
i = a - 2bt { for i = 0 ï€ ï€ &implies;ï€ t =
a
2b
}
From joule's law of heating
dH = i2Rdt
= ï€ïƒ²
a /2b
2
0
H (a 2bt) Rdt
H =
ï€
ï€ ï‚´
a
3 2b
0
(a 2bt) R
3 2b
=
3a R
6b