NEET-XII-Physics

exam-1 year:2016

with Solutions -
  • #6
    In a diffraction pattern due to a single slit
    of width 'a', the first minimum is observed at
    an angle 30° when light of wavelength 5000 Å is
    incident on the slit. The first secondary maximum
    is observed at an angle of :
    (1) ``sin^{-1}(\frac 14)``
    (2) ``sin^{-1}(\frac 23)``
    (3)``sin^{-1}(\frac 12)``
    (4) ``sin^{-1}(\frac 34)``
    digAnsr:   4
    Ans : 4
    Sol. For first minima, sin30°=

    a
    =

    2
    First secondary maxima will be at
    sin =
    3
    2a
    =
     
      
    3 1
    2 2 &implies;
      =   
    1 3sin
    4