NEET-XII-Physics
exam-1 year:2016
- #6In a diffraction pattern due to a single slit
of width 'a', the first minimum is observed at
an angle 30° when light of wavelength 5000 Å is
incident on the slit. The first secondary maximum
is observed at an angle of :
(1) ``sin^{-1}(\frac 14)``
(2) ``sin^{-1}(\frac 23)``
(3)``sin^{-1}(\frac 12)``
(4) ``sin^{-1}(\frac 34)``digAnsr: 4Ans : 4
Sol. For first minima, sin30°=
a
=
2
First secondary maxima will be at
sin =
3
2a
=
3 1
2 2 &implies;
=
1 3sin
4