NEET-XII-Chemistry
Previous Year Paper year:2017
- #15The equilibrium constants of the following are :
``\ce [N2 +3H2 \rightleftarrows 2NH3``]
``\ce [N2 + O2 \rightleftarrows 2NO``]
``\ce [H2 + \frac12 O2 \rightleftarrows H2O``]
The equilibrium constant (K) of the reaction :
``\ce 2NH_3 + \frac52 O_2`` ``\xrightleftharpoons{K}`` ``2NO + 3H_2O``
, will be:
(1) ``K_2^3`` ``K_3/ K_1``
(2)``K_1`` ``K_3^3``/``K_2``
(3) ``K_2`` ``K_3^3``/``K_1``
(4) ``K_2`` ``K_3``/``K_1``digAnsr: 3Ans : (3)
Sol. (1) N2 + 3 H2 2 NH3 K1
(2) N2 + O2 2 NO K2
(3) H2 + 2
1 O2 H2O K3
Object 2 NH3 + 2
5 O2
K 2 NO + 3 H2O
Equation (3) × 3 + (2) - (1)
∴ K =
1
3
32
K
KK ×