NEET-XII-Chemistry
Previous Year Paper year:2017
- #82For a cell involving one electron ``E°_{cell}``= 0.59 V
at 298 K, the equilibrium constant for the cell
reaction is :[Given that ``\frac{2.303 RT}{F}``=0.059V at T = 298 K.
(1) ``1.0 × 10^2``
(2) ``1.0 × 10^5``
(3) ``1.0 × 10^{10}``
(4) ``1.0 × 10^{30}``digAnsr: 3Ans : ( 3 )
Sol.
E
cell
= E°
cell
-
0.059
log Q
n
...(i)
(At equilibrium, Q = K
eq
and E
cell
= 0)
0 = E°
cell
- eq
0.059
logK
1
(from equation (i))
cell
eq
E° 0.59
logK = = = 10
0.059 0.059
K
eq
= 1010 = 1 × 1010