NEET-XII-Chemistry

exam-1 year:2016

with Solutions - page 2

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  • Qstn #60
    The electronic configurations of Eu(Atomic No 63),
    Gd(Atomic No 64) and Tb (Atomic No. 65) are
    (1) [Xe]``4f^76s^2``, [Xe]``4f^8 6s^2`` and [Xe]``4f^85d^16s^2``
    (2) [Xe]``4f^75d^16s^2``, [Xe]``4f^7 5d^1 6s^2`` and [Xe]``4f^96s^2``
    (3) [Xe]``4f^65d^16s^2``, [Xe]``4f^75d^16s^2`` and [Xe]``4f^85d^16s^2``
    (4) [Xe]``4f^76s^2``, [Xe]``4f^75d^16s^2 ``and [Xe]``4f^96s^2``
    digAnsr:   4
    Ans : (4)
    Sol.
  • Qstn #61
    Two electrons occupying the same orbital are
    distinguished by
    (1) Principal quantum number
    (2) Magnetic quantum number
    (3) Azimuthal quantum number
    (4) Spin quantum number
    digAnsr:   4
    Ans : (4)
    Sol. Two electrons occupying the same orbital differ by
    spin quantum number.
  • Qstn #62
    Which copper is heated with conc. ``HNO_3`` it
    produces
    (1) ``Cu(NO_3)_2`` and ``NO_2``
    (2) ``Cu(NO_3)_2`` and NO
    (3) ``Cu(NO_3)_2``, NO and ``NO_2``
    (4) ``Cu(NO_3)_2`` and ``N_2O``
    digAnsr:   1
    Ans : (1)
    Sol. Cu + 4HNO3 (conc.) Cu(NO3)2 + 2NO2+2H2O
  • Qstn #63
    Which of the following reagents would distingusih
    cis-cyclopenta-1,2-diol from the trans-isomer?
    (1) Acetone
    (2) Ozone
    (3) MnO2
    (4) Aluminium isopropxide
    digAnsr:   1
    Ans : (1)
    Sol. ▵G = ▵H - T.▵S
    For, ▵H < 0 and ▵S > 0, ▵G = -ve (always)
    ∴ spontaneous at all temperatures.
  • Qstn #64
    The correct thermodynamic conditions for the
    spontaneous reaction at all temperatures is
    (1)``\triangle``H < 0 and ``\triangle``S = 0
    (2) ``\triangle``H > 0 and ``\triangle``S < 0
    (3) ``\triangle``H < 0 and ``\triangle``S > 0
    (4)``\triangle``H < 0 and ``\triangle``S < 0
    digAnsr:   3
    Ans : (3)
    Sol. ▵G = ▵H - T.▵S
    For, ▵H < 0 and ▵S > 0, ▵G = -ve (always)
    ∴ spontaneous at all temperatures.
  • Qstn #65
    Lithium has a bcc structure. Its density is
    530 ``kg m^{-3}`` and its atomic mass is 6.94 ``g mol^{-1}``.
    Calculate the edge length of a unit cell of Lithium
    metal. (NA = 6.02 × ``10^{23} mol^{-1}``)
    (1) 154 pm
    (2) 352 pm
    (3) 527 pm
    (4) 264 pm
    digAnsr:   2
    Ans : (2)
    Sol.

     =
     3A
    Z M
    N a
    For bcc structure
    Z = 2,  = 530 kg m-3 = 0.530 g cm-3

    =
     23 3
    2 6.94
    0.530
    6.02 10 a
    a3 = 4.348 × 10-23 cm3
    a = 3.52 × 10-8 cm
    a = 352 pm
  • Qstn #66
    Which one of the following orders is correct for the
    bond dissociation enthalpy of halogen molecules?
    (1) ``\ce {I2 > Br2 > Cl2 > F2}``
    (2) ``\ce {Cl2 > Br2 > F2 > I2}``
    (3) ``\ce Br2 > I2 > F2 > Cl2}``
    (4)``\ce { F2 > Cl2 > Br2 > I2}``
    digAnsr:   2
    Ans : (2)
    Sol. C2 > Br2 > F2 > I2

    due to high p-p repulsion
  • Qstn #67
    Which of the following is an analgesic ?
    (1) Novalgin
    (2) Penicillin
    (3) Streptomycin
    (4) Chloromycetin
    digAnsr:   1
    Ans : (1)
    Sol. Novalgin used as analgesic
  • Qstn #68
    Equal moles of hydrogen and oxygen gases are
    placed in a container with a pin-hole through which
    both can escape. What fraction of the oxygen
    escapes in the time required for one-half of the
    hydrogen to escape ?
    (1) 1/8
    (2) 1/4
    (3) 3/8
    (4) 1/2
    digAnsr:   1
    Ans : (1)
    Sol. =
    2 2H O
    n n and =
    2 2H O
    t t
    According to Graham's law
    = &implies; =2 2
    2 2
    H O 1 1
    O H 2 2
    r M v / t 32
    r M v / t 2
    = =
    1 / 2
    16 4
    1 / x
    =
    x
    4
    2
    ∴ x = 8
    ∴ Fraction of O2 = 1/8
  • Qstn #69
    Consider the nitration of benzene using mixed conc.
    ``H_2SO_4`` and ``HNO_3``. If a large amount of ``KHSO_4`` is
    added to the mixture, the rate of nitration will be:-
    (1) faster
    (2) slower
    (3) unchanged
    (4) doubled
    digAnsr:   2
    Ans : (2)
    Sol. Slower, as large amount of HSO4
    - will decrease
    ionisation of H2SO4 that result in lesser ionisation
    of nitric acid and lesser formation of nitronium ion
    [ NO2
    +]
  • Qstn #70
    Predict the correct order among the following :-
    (1) lone pair- lone pair > lone pair - bond pair
    > bond pair - bond pair
    (2) lone pair - lone pair > bond pair - bond pair
    > lone pair - bond pair
    (3) bond pair - bond pair > lone pair - bond pair
    > lone pair - lone pair
    (4) lone pair - bond pair > bond pair - bond pair
    > lone pair - lone pair
    digAnsr:   1
    Ans : (1)
    Sol.
  • Qstn #71
    The product obtained as a result of a reaction of
    nitrogen with ``CaC_2`` is :-
    (1) ``Ca(CN)_2``
    (2) CaCN
    (3)`` CaCN_3``
    (4)`` Ca_2CN``
    digAnsr:   B
    Ans : (Bonus) (Question should beBonous)
    Sol. CaC2 + N2 ``\rightleftharpoons`` CaCN2 + C
  • Qstn #72
    Consider the following liquid - vapour equilibrium.
    Liquid ``\rightleftharpoons`` Vapour
    Which of the following relations is correct ?
    (1) ``\frac {dlnG}{dT^2}``=``\frac {\triangle H_v}{RT^2}``
    (2)``\frac {dlnP}{dT}``=``\frac {-\triangle H_v}{RT}``
    (3)``\frac {dlnP}{dT^2}``=``\frac {-\triangle H_v}{T^2}``
    (4) ``\frac {dlnP}{dT}``=``\frac {\triangle H_v}{RT^2}``
    digAnsr:   4
    Ans : (4)
    Sol. Clausius - Clapeyron's equation

    = V
    2
    Hd lnP
    dT RT
  • Qstn #73
    Match the compounds given in column I with the
    hybridisation and shape given in column II and mark
    the correct option.
    Column-I Column-II
    a) ``XeF_6`` (i) Distorted
    octahedral
    (b) ``XeO_3`` (ii) Square planar
    (c) ``XeOF_4`` (iii) pyramidal
    (d) ``XeF_4`` (iv) Square
    pyramidal
    Code :-
    a) (b) (c) (d)
    (1) (i) (iii) (iv) (ii)
    (2) (i) (ii) (iv) (iii)
    (3) (iv) (iii) (i) (ii)
    (4) (iv) (i) (ii) (iii)
    digAnsr:   1
    Ans : (1)
    Sol.
    Xe
    F
    F
    F
    FF
    F ..
    XeF6
    distorted
    octahedral
    Xe
    O
    ..
    XeO3
    O
    O
    Pyramidal
    Xe
    O
    F
    FF
    F
    XeOF4
    Square
    pyramidal
    ..
    Xe
    F
    FF
    F
    XeF4
    Square
    planar
    ..
    ..
  • Qstn #74
    Which of the following has longest C-O bond
    length? (Free C-O bond length in Co is 1.128Å).
    (1) ``Ni(CO)_4``
    (2) ``[Co(CO)_4]^\circleddash ``
    (3) ``[Fe(CO)_4]^{2-}``
    (4) ``[Mn(CO)_6]^+``
    digAnsr:   3
    Ans : (3)
    Sol. [Fe(CO)4]2-
    Since metal atom is carrying maximum -ve charge
    therefore it would show maximum synergic bonding
    as sa resultant C-O bond length would be
    maximum.