NEET-XII-Physics

13: Nuclei

page 3
  • #25
    A source contains two phosphorous radio nuclides (T1/2 = 14.3d) and (T1/2 = 25.3d). Initially, 10% of the decays come from. How long one must wait until 90% do so?
    Ans : Half life of, T1/2 = 14.3 days

    Half life of, T’1/2 = 25.3 days

    nucleus decay is 10% of the total amount of decay.

    The source has initially 10% of nucleus and 90% of nucleus.

    Suppose after t days, the source has 10% of nucleus and 90% of nucleus.

    Initially:

    Number of nucleus = N

    Number of nucleus = 9 N

    Finally:

    Number of

    Number of

    For nucleus, we can write the number ratio as:



    For, we can write the number ratio as:



    On dividing equation (1) by equation (2), we get:



    Hence, it will take about 208.5 days for 90% decay of .